按键上的JTable编辑

Question

我试图以编程方式开始编辑JTable按键上的当前行的第三列.

我已经实现了一个keyReleased()包含此代码的KeyListener

if (e.getKeyCode() == KeyEvent.VK_ENTER)
{
    myTab.changeSelection(myTab.getSelectedRow(), 2, true, false);
    myTab.editCellAt(myTab.getSelectedRow(), 2);
}

当我释放回车时,单元格确实可以编辑(我可以在最后键入),但没有插入符号.

当我用鼠标点击时,行为是预期的(我可以编辑和carret存在).

另外,我注意到在keyrelease上,我的celleditor是null,并且在mouseclick上它不是null.

我究竟做错了什么？

Answer 1

避免KeyListener,当涉及到焦点和调度事件的顺序时,它是不可靠的(在听众之前可以让他们锁定密钥,因此永远不会得到通知).

使用键绑定,而不是

InputMap im = table.getInputMap(JTable.WHEN_ANCESTOR_OF_FOCUSED_COMPONENT);
ActionMap am = table.getActionMap();

KeyStroke enterKey = KeyStroke.getKeyStroke(KeyEvent.VK_ENTER, 0);

im.put(enterKey, "Action.enter");
am.put("Action.enter", new AbstractAction() {
    public void actionPerformed(ActionEvent evt) {
        table.changeSelection(table.getSelectedRow(), 2, false, false);
        if (!table.editCellAt(table.getSelectedRow(), 2)) {
            JOptionPane.showMessageDialog(table, "Failed to start cell editing");
        }
    }
});

我也怀疑这个myTab.changeSelection(myTab.getSelectedRow(), 2, true, false);电话.JavaDocs基本上说......

toggle:true,extend:false.如果选择了指定的单元格,请取消选择它.如果未选中,请选择它.

这对我来说,如果当前选择了单元格,它将被取消选中.

更新了工作示例

public class TestTableEditor {

    public static void main(String[] args) {
        new TestTableEditor();
    }

    private JTable table;

    public TestTableEditor() {
        EventQueue.invokeLater(new Runnable() {
            @Override
            public void run() {
                try {
                    UIManager.setLookAndFeel(UIManager.getSystemLookAndFeelClassName());
                } catch (ClassNotFoundException | InstantiationException | IllegalAccessException | UnsupportedLookAndFeelException ex) {
                }

                table = new JTable(new MyTableModel());
                InputMap im = table.getInputMap(JTable.WHEN_ANCESTOR_OF_FOCUSED_COMPONENT);
                ActionMap am = table.getActionMap();

                KeyStroke enterKey = KeyStroke.getKeyStroke(KeyEvent.VK_ENTER, 0);

                im.put(enterKey, "Action.enter");
                am.put("Action.enter", new AbstractAction() {
                    public void actionPerformed(ActionEvent evt) {
                        table.changeSelection(table.getSelectedRow(), 1, false, false);
                        if (!table.editCellAt(table.getSelectedRow(), 1)) {
                            JOptionPane.showMessageDialog(table, "Failed to start cell editing");
                        }
                    }
                });

                JFrame frame = new JFrame();
                frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
                frame.setLayout(new BorderLayout());
                frame.add(new JScrollPane(table));
                frame.pack();
                frame.setLocationRelativeTo(null);
                frame.setVisible(true);
            }
        });
    }

    public class MyTableModel extends AbstractTableModel {

        @Override
        public int getRowCount() {
            return 1;
        }

        @Override
        public int getColumnCount() {
            return 3;
        }

        @Override
        public Object getValueAt(int rowIndex, int columnIndex) {
            Object value = null;
            switch (columnIndex) {
                case 0:
                    value = "Can't edit";
                    break;
                case 1:
                    value = "Edit me";
                    break;
                case 2:
                    value = "Can't edit";
                    break;
            }
            return value;
        }

        @Override
        public boolean isCellEditable(int rowIndex, int columnIndex) {
            return columnIndex == 1;
        }
    }
}

更新

在所有愚蠢,痛苦,难以找到...

添加table.setSurrendersFocusOnKeystroke(true);到您的代码......

设置当由于JTable转发单元的键盘事件而激活编辑器时,此JTable中的编辑器是否获得键盘焦点.默认情况下,此属性为false,并且除非单击单元格,否则JTable将保留焦点.