使用bash从文件中提取文本

Question

我是Linux新手,有一个非常大的文本日志文件可供从中提取.我以为要用bash？

例如,该文件包含:

Node:xyz
Time:01/07/13 14:26:17
INFO: Trusted certif ok

Node:abc
Time:01/07/13 14:26:18
INFO: Trusted certif ok

Node:def
Time:01/07/13 14:26:18
INFO: Trusted certif not ok

我需要在Node之后提取文本:并将其添加到Info之后的文本:要显示在一行上,输出要重定向到新文件.我正在尝试awk和sed,但还没想到它.非常感谢.

示例输出如下所示:

xyz Trusted certif ok
abc Trusted certif ok
dbf Trusted certif not ok

Answer 1

试着这样做:

在awk

awk -F: '/^Node/{v=$2}/^INFO/{print v $2}' file.txt

在bash中:

while IFS=: read -r c1 c2; do
    [[ $c1 == Node ]] && var=$c1
    [[ $c1 == INFO ]] && echo "$var$c2"
done < file.txt

in perl:

perl -F: -lane '
    $v = $F[1] if $F[0] eq "Node";
    print $v, $F[1] if $F[0] eq "INFO"
' file.txt

在python中(在文件中,用法:) ./script.py file.txt:

import sys
file = open(sys.argv[1])
while 1:
    line = file.readline()
    tpl = line.split(":")
    if tpl[0] == "Node":
        var = tpl[0]
    if tpl[0] == "INFO":
        print var, tpl[1]
    if not line:
        break