如何用两把键对lambda进行排序？

Question

我用这个

ThreadList.append([''.join(map(str,[Thread])), date, rrf[5]])

SendThreadList = ''

ThreadList = sorted(ThreadList, key=lambda Entry: Entry[1], reverse=True)
ThreadList = sorted(ThreadList, key=lambda Entry: Entry[2], reverse=True)

排序显示只有第二个排序,怎么做排序与两个entrys键？

Answer 1

如果你想按Entry [1]排序,然后输入[2],那么你将lambda作为一个元组返回...:

ThreadList = sorted(ThreadList, key=lambda Entry: (Entry[1], Entry[2]), reverse=True)

什么有时更具可读性(并且可能稍快)是使用operator模块和使用key=operator.itemgetter(1, 2)