阅读Cassandra 1.2表与pycassa

Question

使用Cassandra 1.2.我通过以下方式使用CQL 3创建了一个表:

CREATE TABLE foo (
    user text PRIMARY KEY,
    emails set<text>
);

现在我试图通过pycassa查询数据:

import pycassa
from pycassa.pool import ConnectionPool
pool = ConnectionPool('ks1', ['localhost:9160'])
foo = pycassa.ColumnFamily(pool, 'foo')

这给了我

Traceback (most recent call last):
  File "test.py", line 5, in <module>
    foo = pycassa.ColumnFamily(pool, 'foo')
  File "/home/john/src/pycassa/lib/python2.7/site-packages/pycassa/columnfamily.py", line 284, in __init__
    self.load_schema()
  File "/home/john/src/pycassa/lib/python2.7/site-packages/pycassa/columnfamily.py", line 312, in load_schema
    raise nfe
pycassa.cassandra.ttypes.NotFoundException: NotFoundException(_message=None, why='Column family foo not found.')

如何实现这一目标？

Answer 1

如果您使用CQL3创建了表,并且希望通过基于thrift的客户端访问它们; 您必须指定Compact Storage属性.例如:

CREATE TABLE dummy_file_test
(
 dtPtn          INT,
 pxID           INT,
 startTm        INT,
 endTm          INT,
 patID          BIGINT,
 efile          BLOB,
 PRIMARY KEY((dtPtn, pxID, startTm))
)with compact storage;  

这是我在使用Pycassa访问基于CQL3的列族时必须要做的事情