从多个范围中选择多个值

Question

可能重复:
在SQL中,如何在范围内"分组"？

我有那样的桌子

price
id  |  prices
1   |   3910
2   |   4125
3   |   3740
4   |   2700
5   |   1600
6   |   2150
7   |   2430

我希望的输出是这样的

1500-1999  |  2000-2499 | 2500-2999  | 3000-3499 | 3500-3999 | 4000-4499  |   allvalues
--------------------------------------------------------------------------------------
   1       |      2     |      1     |     0     |     2     |     1      |   7

expli:

• 1500-1999 - >意味着我想要1500到1999之间的计数数字,依此类推.

• 所有值都是计算所有值.

  *如果有人需要在那里测试它,这里是sql小提琴.

希望一切都清楚,谢谢你的帮助.

Answer 1

这是一种使用范围的枢轴.对于使用的数据透视查询,模式是相同的SUM(CASE...)

SELECT
  SUM(CASE WHEN prices BETWEEN 1500 AND 1999 THEN 1 ELSE 0 END) AS `1500-1999`,
  SUM(CASE WHEN prices BETWEEN 2000 AND 2499 THEN 1 ELSE 0 END) AS `2000-2499`,
  SUM(CASE WHEN prices BETWEEN 2500 AND 2999 THEN 1 ELSE 0 END) AS `2500-2999`,
  SUM(CASE WHEN prices BETWEEN 3000 AND 3499 THEN 1 ELSE 0 END) AS `3000-3499`,
  SUM(CASE WHEN prices BETWEEN 3500 AND 3999 THEN 1 ELSE 0 END) AS `3500-3999`,
  ...
  COUNT(*) AS `All Values`
FROM
  prices

替换其余的范围... CASE如果条件匹配则产生0或1,并且由聚合SUM()s 加起来.

http://sqlfiddle.com/#!2/5803e/10