and*_*ung 18 c++ lambda calling-convention visual-c++ c++11
我想将嵌套在类中的lambda函数指针传递给Windows API回调函数.我发现没有地方可以指定__stdcall
关键字.有人告诉我,只编译支持__cdecl
,但我用nm命令之后转储OBJ文件,我发现编译将产生三个辅助函数(__stdcall
,__cdecl
,__fastcall
)同时进行.所以我的问题是,如何指定调用约定?
以下代码是我的测试代码.
#include "stdafx.h"
int _tmain(int argc, _TCHAR* argv[])
{
auto func = [](){};
return 0;
}
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00000000 t ?<helper_func_cdecl>@<lambda_5738939ec88434c53e1a446c47cf2db6>@@CAXXZ
00000000 t ?<helper_func_fastcall>@<lambda_5738939ec88434c53e1a446c47cf2db6>@@CIXXZ
00000000 t ?<helper_func_stdcall>@<lambda_5738939ec88434c53e1a446c47cf2db6>@@CGXXZ
00000000 t ??B<lambda_5738939ec88434c53e1a446c47cf2db6>@@QBEP6AXXZXZ
00000000 t ??B<lambda_5738939ec88434c53e1a446c47cf2db6>@@QBEP6GXXZXZ
00000000 t ??B<lambda_5738939ec88434c53e1a446c47cf2db6>@@QBEP6IXXZXZ
00000000 t ??R<lambda_5738939ec88434c53e1a446c47cf2db6>@@QBEXXZ
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ild*_*arn 18
施展它:
WinApiFunc(static_cast<void(__stdcall *)()>(func));
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或者首先将它存储到局部变量中:
void (__stdcall *funcp)() = func;
WinApiFunc(funcp);
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