use*_*037 11 core-data nsfetchrequest ios
目的:我想从数据库(核心数据)中获取一个属性(从实体)到数组的值.
例
实体名称=员工
Attribute = employeeID
我只想将所有employeeID填充到数组/集中.
题
鉴于以下是我的实现,我只觉得它是一种圆形的方式,我想知道是否有更好的方法来做到这一点.
码
NSFetchRequest *fetchRequest = [NSFetchRequest fetchRequestWithEntityName:@"Employees"];
fetchRequest.resultType = NSDictionaryResultType;
[fetchRequest setPropertiesToFetch:[NSArray arrayWithObjects:@"employeeID", nil]];
NSError *error = nil;
NSArray *results = [self.managedObjectContext executeFetchRequest:fetchRequest
error:&error];
NSMutableArray *employeeIDs = [NSMutableArray array];
for(id currentRecord in results)
{
[employeeIDs addObject:[currentRecord objectForKey:@"employeeID"]];
}
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iDe*_*Dev 23
你可以避免最后一个循环,
代替,
NSMutableArray *employeeIDs = [NSMutableArray array];
for(id currentRecord in results)
{
[employeeIDs addObject:[currentRecord objectForKey:@"employeeID"]];
}
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试试这个,
NSMutableArray *employeeIDs = [results valueForKey:@"employeeID"];
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Rah*_*ade 17
一种方法是 -
NSFetchRequest *fetchRequest = [NSFetchRequest fetchRequestWithEntityName:@"Employees"];
fetchRequest.resultType = NSDictionaryResultType;
NSError *error = nil;
NSArray *results = [self.managedObjectContext executeFetchRequest:fetchRequest
error:&error];
NSMutableArray *employeeIDs = [results valueForKey:@"employeeID"];
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