boost::msm - 一种获取状态的字符串表示(即 getName)的方法?

use*_*039 6 c++ boost-msm

我正在尝试使用 boost::msm 库在我的代码中创建一个状态机。有谁知道一种获取状态的字符串名称(不是 int id)的方法吗?我正在尝试将其用于日志记录/调试目的。例如,在 no_transition 函数中,我获得了状态 ID,但我正在尝试获得一个名称,以便更容易阅读:

template <class Event ,class Fsm>
    void no_transition(Event const& e, Fsm& fsm, int stateId)
    {
        //This is what I'm trying: 
        auto state = fsm.get_state_by_id(stateId); //This returns a boost::msm::front::default_base_state. Anything I can override in there to set a name?
        const char* stateName = state->getStateName(); //I want to do something like this since I can do e.getEventId()

        print("FSM rejected the event %s as there is no transition from current state %s (%d)\n", e.getEventId(), stateName, stateId);
    }
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这是我定义事件和状态的方式: 状态:

struct Idle : front::state<> {
 static const char* const getStateName() {
        return "Idle";
    }
};
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事件:

struct SampleEvent {
    SampleEvent() {}
    static const char* const getEventId() {
        return "SampleEvent";
    }
};
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任何想法都会很棒。谢谢!

Kik*_*sha 5

您可以使用以下代码实现所需的效果:

 #include <boost/msm/back/tools.hpp>
 #include <boost/msm/back/metafunctions.hpp>
 #include <boost/mpl/for_each.hpp>
  .......
  .......
    template <class Event ,class Fsm>
    void no_transition(Event const& e, Fsm& fsm, int stateId){
        typedef typename boost::msm::back::recursive_get_transition_table<FSM>::type recursive_stt;
        typedef typename boost::msm::back::generate_state_set<recursive_stt>::type all_states;
        std::string stateName;
        boost::mpl::for_each<all_states,boost::msm::wrap<boost::mpl::placeholders::_1> >(boost::msm::back::get_state_name<recursive_stt>(stateName, state));
        std::cout << "No transition from state: " << stateName << std::endl;}
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  • 最后,您可以使用 `boost::core::demangle(stateName.c_str())` 对 `stateName` 进行解构。 (3认同)

rop*_*eur 4

  1. 最佳选择:使用访客。
    看看http://www.boost.org/doc/libs/1_53_0/libs/msm/doc/HTML/examples/SM-2Arg.cpp

  2. 使用 no_transition 的最后一个参数(state_id),您可以从数组中检索名称:

    static char const* const state_names[] = { "State1", "State2", ... };
    打印(状态名称[状态ID]);

请注意,状态 ID 仅用于调试目的。ID是在编译时生成的,取决于转换表中条目的顺序

MSM 文档参考: