我正在尝试使用 boost::msm 库在我的代码中创建一个状态机。有谁知道一种获取状态的字符串名称(不是 int id)的方法吗?我正在尝试将其用于日志记录/调试目的。例如,在 no_transition 函数中,我获得了状态 ID,但我正在尝试获得一个名称,以便更容易阅读:
template <class Event ,class Fsm>
void no_transition(Event const& e, Fsm& fsm, int stateId)
{
//This is what I'm trying:
auto state = fsm.get_state_by_id(stateId); //This returns a boost::msm::front::default_base_state. Anything I can override in there to set a name?
const char* stateName = state->getStateName(); //I want to do something like this since I can do e.getEventId()
print("FSM rejected the event %s as there is no transition from current state %s (%d)\n", e.getEventId(), stateName, stateId);
}
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这是我定义事件和状态的方式: 状态:
struct Idle : front::state<> {
static const char* const getStateName() {
return "Idle";
}
};
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事件:
struct SampleEvent {
SampleEvent() {}
static const char* const getEventId() {
return "SampleEvent";
}
};
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任何想法都会很棒。谢谢!
您可以使用以下代码实现所需的效果:
#include <boost/msm/back/tools.hpp>
#include <boost/msm/back/metafunctions.hpp>
#include <boost/mpl/for_each.hpp>
.......
.......
template <class Event ,class Fsm>
void no_transition(Event const& e, Fsm& fsm, int stateId){
typedef typename boost::msm::back::recursive_get_transition_table<FSM>::type recursive_stt;
typedef typename boost::msm::back::generate_state_set<recursive_stt>::type all_states;
std::string stateName;
boost::mpl::for_each<all_states,boost::msm::wrap<boost::mpl::placeholders::_1> >(boost::msm::back::get_state_name<recursive_stt>(stateName, state));
std::cout << "No transition from state: " << stateName << std::endl;}
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最佳选择:使用访客。
看看http://www.boost.org/doc/libs/1_53_0/libs/msm/doc/HTML/examples/SM-2Arg.cpp
使用 no_transition 的最后一个参数(state_id),您可以从数组中检索名称:
static char const* const state_names[] = { "State1", "State2", ... };
打印(状态名称[状态ID]);
请注意,状态 ID 仅用于调试目的。ID是在编译时生成的,取决于转换表中条目的顺序
MSM 文档参考: