如何将数据绑定到Xaml,Windows Phone?

Pak*_*pus 2 data-binding xaml json windows-phone-7

这是我的C#代码,现在它在控制台中显示数据.

class PlaceViewModel
    {

        public List<Vantaa.IntroPage.Place> Places;
    }       

public class Place
            {
                public string id { get; set; }
                public string title { get; set; }
                public string latitude { get; set; }
                public string longitude { get; set; }
                public string www { get; set; }
            }

        public class RootObject
        {
            public List<Place> Places { get; set; }
        }

    protected override void OnNavigatedTo(NavigationEventArgs e)
        {
            WebClient webClient = new WebClient();
            webClient.DownloadStringCompleted += new DownloadStringCompletedEventHandler(webClient_DownloadStringCompleted);
            webClient.DownloadStringAsync(new Uri("http://mobiilivantaa.lightscreenmedia.com/api/place"));
        }

        private void webClient_DownloadStringCompleted(object sender, DownloadStringCompletedEventArgs e)
        {
            var rootObject = JsonConvert.DeserializeObject<RootObject>(e.Result);

            foreach (var book in rootObject.Places)
            {
                System.Diagnostics.Debug.WriteLine(book.id);
            }
            this.DataContext = new PlaceViewModel
                 {
                      Places = rootObject.Places
                 };
            }
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我应该怎么处理xaml文件才能在textblock中显示数据?

这是我目前的xaml代码.它肯定不起作用.我真的不知道.

<ListBox ItemsSource="{Binding Places}">
            <ListBox.ItemTemplate>
                <DataTemplate>
                    <Grid>
                        <TextBlock Text="{Binding Path=id}" />
                    </Grid>
                </DataTemplate>
            </ListBox.ItemTemplate>
        </ListBox>
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Abb*_*bas 5

你的类代码看起来不错,所以现在只需要将结果绑定到视图.您将返回一个对象列表,因此您应该使用支持显示多个项目的控件.当然,您可以将书籍的所有ID连接到一个字符串并在标签中显示.但这不是它的完成方式.你应该做的是将一个ListBox控件添加到XAML并在其中创建一个DataTemplate.这样您就可以设置项目的显示方式.

创建一个将成为XAML页面的ViewModel的类.这个类将有一个属性'Places'(类型:) List<Place>.在完成所有数据的OnNavigatedTo事件中,填充ViewModel并绑定并将其绑定到XAML的DataContext:

this.DataContext = new YourViewModel { Places = rootObject.Places };
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这样,您可以从XAML中的ViewModel中获取所有对象:

<ListBox ItemsSource="{Binding Places}">
    <ListBox.ItemTemplate>
        <DataTemplate>
            <Grid>
                <TextBlock Text="{Binding Path=id}" />
            </Grid>
        </DataTemplate>
    </ListBox.ItemTemplate>
</ListBox>
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编辑:

这是一个有效的例子:

XAML:

<Grid>
    <ListBox ItemsSource="{Binding Places}">
        <ListBox.ItemTemplate>
            <DataTemplate>
                <StackPanel Orientation="Horizontal">
                    <TextBlock Text="{Binding Path=ID}" />
                    <TextBlock Text="{Binding Path=Title}" />
                </StackPanel>
            </DataTemplate>
        </ListBox.ItemTemplate>
    </ListBox>
</Grid>
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Place.cs:

public class Place
{
    public string ID { get; set; }
    public string Title { get; set; }
    public string Latitude { get; set; }
    public string Longitude { get; set; }
    public string Web { get; set; }
}
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MainViewModel.cs:

public class MainViewModel
{
    public MainViewModel()
    {
        Places = new List<Place>();
    }

    public List<Place> Places { get; set; }
}
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示例存储库(您应该拥有自己的存储库):

public static List<Place> FetchData()
{
    var lst = new List<Place>();

    lst.Add(new Place { ID = "1", Title = "One", Latitude = "111", Longitude = "111", Web = "www......" });
    lst.Add(new Place { ID = "2", Title = "Two", Latitude = "222", Longitude = "222", Web = "www......" });
    lst.Add(new Place { ID = "3", Title = "Three", Latitude = "333", Longitude = "333", Web = "www......" });
    lst.Add(new Place { ID = "4", Title = "Four", Latitude = "444", Longitude = "444", Web = "www......" });

    return lst;
}
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MainWindow.xaml.cs:

public MainWindow()
{
    InitializeComponent();
    //This is where the magic happens
    //Fill the viewModel with the data
    var viewModel = new MainViewModel { Places = Repository.FetchData() };
    //Assign the viewModel with the data to the DataContext
    //The bindings will be automatically done in the XAML
    DataContext = viewModel;
}
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