如何在Android App中使用AsYouTypeFormatter TextWatcher？

Question

我正在尝试使用来自Google的libphonenumber的AsYouTypeFormatter和TextWatcher,我不确定它是否可行.我已经能够将文本格式化为从EditText字段输入并将其输出到另一个EditText但不能直接更改原始的EditText字段(这就是我想要的).我知道phoneNumberFormattingTextWatcher,但我们希望用户能够最终选择他们所在的区域设置,并且比使用允许的区域具有更多的控制权(从我收集的内容).

顶级:

private View phoneNumberView;
private EditText phoneNumberText;
private String formattedPhoneNumber;
private boolean isInAfterTextChanged;
private AsYouTypeFormatter aytf;

首先,我在我的类顶部初始化AsYouTypeFormatter:

aytf = PhoneNumberUtil.getInstance().getAsYouTypeFormatter(Locale.getDefault().getCountry());

在创建了我的标签之后,我创建一个EditText框,格式化其中的现有电话号码(可以工作),并附加监听器(这是当前的类):

phoneNumberView = inflater.inflate(R.layout.phone_number_setting, null);
phoneNumberText = (EditText) phoneNumberView.findViewById(R.id.dirty_phone_number);
phoneNumberText.setText(dirtyPhoneNumber);
for (int i = 0; i < dirtyPhoneNumber.length(); i++){
    phoneNumberText.setText(aytf.inputDigit(dirtyPhoneNumber.charAt(i)));
}
aytf.clear();
phoneNumberText.setText(dirtyPhoneNumber);
phoneNumberText.addTextChangedListener(this);

那么这就是我目前在TextWatcher函数中所拥有的,我不确定我的代码中应该包含哪些函数:

@Override
public void afterTextChanged(Editable s) {
    if (!isInAfterTextChanged) {
           isInAfterTextChanged = true;

           if(s.length() > 0){
               Log.v("AsYouTypeFormatter - source", s.toString());
               for(int i = 0; i < s.length(); i++){
                   formattedPhoneNumber = aytf.inputDigit(s.charAt(i));
                   Log.v("AsYouTypeFormatter - formatted", formattedPhoneNumber);

               }
               Log.v("AsYouTypeFormatter - source after loop", s.toString());
             //The formatted output shows properly in this EditText but not when I try to put it back into the original one (phoneNumberText) 
               EditText testPhoneNumberText = (EditText) phoneNumberView.findViewById(R.id.testPhoneNumberText);  
               testPhoneNumberText.setText(formattedPhoneNumber);
               aytf.clear();
           }

           formattedPhoneNumber = null;
           isInAfterTextChanged = false;
       }        

}

@Override
public void beforeTextChanged(CharSequence s, int start, int count,
        int after) {
}

@Override
public void onTextChanged(CharSequence s, int start, int before, int count) {
}

以下是记录输出的示例,因此我知道格式化正在运行:

01-03 10:55:02.838: V/AsYouTypeFormatter - source(27114): 15552451234
01-03 10:55:02.838: V/AsYouTypeFormatter - formatted(27114): 1
01-03 10:55:02.838: V/AsYouTypeFormatter - formatted(27114): 15
01-03 10:55:02.838: V/AsYouTypeFormatter - formatted(27114): 1 55
01-03 10:55:02.838: V/AsYouTypeFormatter - formatted(27114): 1 555
01-03 10:55:02.838: V/AsYouTypeFormatter - formatted(27114): 1 555-2
01-03 10:55:02.838: V/AsYouTypeFormatter - formatted(27114): 1 555-24
01-03 10:55:02.850: V/AsYouTypeFormatter - formatted(27114): 1 555-245
01-03 10:55:02.850: V/AsYouTypeFormatter - formatted(27114): 1 555-245-1
01-03 10:55:02.850: V/AsYouTypeFormatter - formatted(27114): 1 555-245-12
01-03 10:55:02.850: V/AsYouTypeFormatter - formatted(27114): 1 555-245-123
01-03 10:55:02.850: V/AsYouTypeFormatter - formatted(27114): 1 555-245-1234
01-03 10:55:02.850: V/AsYouTypeFormatter - source after loop(27114): 15552451234

这里是输出的图像(顶部EditText是phoneNumberText,底部是testPhoneNumberText):http://imgur.com/GXwRu.png

我想知道的是如何将格式化的输出恢复到原始的EditText中,因为它正在输入？当我尝试这样做时,奇怪的事情发生就像复制一样,或只是显示它没有格式化.我尝试过使用s.replace(),但我不确定我是否正确使用它.这可能吗？谢谢？

Answer 1

对于那些只想在用户输入的EditText中格式化用户输入的电话号码的其他人来说,使用它PhoneNumberFormattingTextWatcher(内置于Android)比尝试任何这些冗长的答案要容易得多 - 而且它是一行代码!

//Add a special listener for this instance that will format phone numbers on the fly.
this.editText.addTextChangedListener(new PhoneNumberFormattingTextWatcher());

你也可以传递用户选择的区域,我认为这实际上会回答OP的问题,但是在API 21之前它是不可用的:

//This version takes a country code!
this.editText.addTextChangedListener(new PhoneNumberFormattingTextWatcher("US"));

Answer 2

我最终在顶部声明了一个新的String：

private String unformattedPhoneNumber;

然后将我的代码更改为此：

@Override
public void afterTextChanged(Editable s) {
if (!isInAfterTextChanged) {
       isInAfterTextChanged = true;

       if(s.length() > 0){
           Log.v("AsYouTypeFormatter - source", s.toString());
           unformattedPhoneNumber = s.toString().replaceAll("[^\\d.]", "");
           for(int i = 0; i < unformattedPhoneNumber.length(); i++){
               formattedPhoneNumber = aytf.inputDigit(unformattedPhoneNumber.charAt(i));
               Log.v("AsYouTypeFormatter - formatted", formattedPhoneNumber);

           }
           Log.v("AsYouTypeFormatter - source after loop", s.toString());

           phoneNumberText.setText(formattedPhoneNumber);

           aytf.clear();
       }

       formattedPhoneNumber = null;
       isInAfterTextChanged = false;
   }        

}

看来aytf无法格式化已经部分格式化的电话号码，因此我必须在重新提交给aytf之前剔除所有非数字？现在剩下的唯一问题是EditText字段中的光标位于开头而不是结尾，但这不是要解决的问题。好极了。

编辑代码：

@Override
public void afterTextChanged(Editable s) {
    if (!isInAfterTextChanged) {
        isInAfterTextChanged = true;
        phoneNumberText.setText(pnu.updateNationalNumber(s.toString()));
        phoneNumberText.setSelection(this.phoneNumberText.getText().length());
        isInAfterTextChanged = false;
    }
}

 /**
 * Updates the national number based on the param s
 * Takes all formatting out of param s and then reformats the number
 * using the AsYouTypeFormatter for libphonenumber and based upon
 * the region code
 *  
 * @param s The formatted value to be used to update the national number
 * @return String The new formatted national number
 */
public String updateNationalNumber(String s){
    //Instantiate the as you type formatter with the current region (US or UK)
    aytf = phoneUtil.getAsYouTypeFormatter(this.currentRegionCode.getCountryCode());
    String fNationalNumber = null;

    //Format the string
    if(s.length() > 0){
        String digitString = null;
        //If it's in the US remove all leading 1s (international code)
        if(this.currentRegionCode == RegionCode.US){
            digitString = new String(s.replaceAll("(^[1?])|([^\\d.])", ""));
        }
        //If it's in the UK remove all leading 44s (international code)
        else if (this.currentRegionCode == RegionCode.GB){
            digitString = new String(s.replaceAll("(^[4?]{2})|([^\\d.])", ""));
        }
       if(digitString != null){
           //RE input all of the digits into the formatter
           for(int i = 0; i < digitString.length(); i++){
               fNationalNumber = aytf.inputDigit(digitString.charAt(i));
           }
       }

       //Clear the formatter for the next round of input
       aytf.clear();

       //Try to update the phone number with the formatted number
       try {
           phoneUtil.parse(fNationalNumber, this.currentRegionCode.getCountryCode(), this.uPhoneNumber);
       //Rejects if the number isn't in an acceptable format for the region code given etc.
       } catch (NumberParseException e) {
          System.err.println("NumberParseException was thrown: " + e.toString());
       }
    }
    //Return the formatted phone number
    return fNationalNumber;
}