python:在pdb中是否可以在n次点击后才启用断点？

Question

在eclipse(以及其他几个IDE)中,有一个选项可以在一定数量的命中之后打开断点.在Python中pdb,断点有一个命中计数,并且有condition命令.我如何连接它们？

Answer 1

条件断点可以通过两种方式设置 -

FIRST:指定使用时设置断点的条件break

python -m pdb pdb_break.py
> .../pdb_break.py(7)<module>()
-> def calc(i, n):
(Pdb) break 9, j>0
Breakpoint 1 at .../pdb_break.py:9

(Pdb) break
Num Type         Disp Enb   Where
1   breakpoint   keep yes   at .../pdb_break.py:9
        stop only if j>0

(Pdb) continue
i = 0
j = 0
i = 1
> .../pdb_break.py(9)calc()
-> print 'j =', j

(Pdb)

SECOND:条件也可以使用该condition命令应用于现有断点.参数是断点ID和表达式.

$ python -m pdb pdb_break.py
> .../pdb_break.py(7)<module>()
-> def calc(i, n):
(Pdb) break 9
Breakpoint 1 at .../pdb_break.py:9

(Pdb) break
Num Type         Disp Enb   Where
1   breakpoint   keep yes   at .../pdb_break.py:9

(Pdb) condition 1 j>0

(Pdb) break
Num Type         Disp Enb   Where
1   breakpoint   keep yes   at .../pdb_break.py:9
        stop only if j>0

(Pdb)

资源

更新:我写了一个更简单的代码

import pdb; pdb.set_trace()
for i in range(100):
    print i

在终端上调试 -

$ python 1.py 
> /code/python/1.py(3)<module>()
-> for i in range(100):
(Pdb) l
  1     
  2     import pdb; pdb.set_trace()
  3  -> for i in range(100):
  4         print i
[EOF]
(Pdb) break 4, i==3
Breakpoint 1 at /code/python/1.py:4
(Pdb) break
Num Type         Disp Enb   Where
1   breakpoint   keep yes   at /code/python/1.py:4
    stop only if i==3
(Pdb) c
0
1
2
> /Users/srikar/code/python/1.py(4)<module>()
-> print i
(Pdb) p i
3

Answer 2

我找到了答案.实际上很简单,有一个命令叫做ignore让你说你想要在1000次点击之后在第9行的断点处突破:

b 9

输出: Breakpoint 2 at ...

ignore 1 1000

输出: Will ignore next 1000 crossings of breakpoint 1.

 c