who*_*boy 10 .net c# linq json json.net
当我尝试使用Newtonsoft.Json解析我的JSON时,我收到以下错误
Response result = JsonConvert.DeserializeObject<Response>(unfilteredJSONData);
无法将属性字符串添加到Newtonsoft.Json.Linq.JObject.对象上已存在具有相同名称的属性.
我无法控制JSON提要,他们只是添加了flags1和flags2.重复的字符串似乎导致错误,但我对如何解决它没有任何好主意.在添加新字段之前,此代码运行良好.
更新:
第一个错误是由使用过时版本的JSON.net引起的.我使用的CMS系统有一个内置版本,它是3.5.当我使用4.5时,我收到一个新错误:
无法将Newtonsoft.Json.Linq.JValue添加到Newtonsoft.Json.Linq.JObject.
事实证明我的JSON与我正在处理的格式不完全相同.请注意更新.错误似乎是由此引起的:
"flags1": {
"string": "text",
"string": "text"
},
JSON是:
{
"result":
{
"lookups":
[
{
"groups":
[
{
"item0": "text",
"item1": "text",
"item2": 0,
"item3": 0,
"item4": 11.5,
"item5": true
},
{
"item6": "text",
"oddName": "text"
},
{
"item7": {
"subitem0": "text",
"subitem1": 0,
"subitem2": true
},
"item8": {
"subitem0": "string",
"subitem1": 0,
"subitem2": true
}
},
{
"url": "http://google.com",
"otherurl": "http://yahoo.com",
"alturllist": [],
"altotherurl": []
},
{},
{
"flags1": {
"string": "text"
},
"flags2": {
"string": "text"
}
}
]
},
{
"groups":
[
{
"item0": "text",
"item1": "text",
"item2": 0,
"item3": 0,
"item4": 11.5,
"item5": true
},
{
"item6": "text",
"oddName": "text"
},
{
"item7": {
"subitem0": "text",
"subitem1": 0,
"subitem2": true
},
"item8": {
"subitem0": "string",
"subitem1": 0,
"subitem2": true
}
},
{
"url": "http://google.com",
"otherurl": "http://yahoo.com",
"alturllist": [],
"altotherurl": []
},
{},
{
"flags1": {
"string": "text",
"string": "text"
},
"flags2": {}
}
]
}
]
}
}
C#类是:
// response
[DataContract]
public class Response
{
[DataMember(Name = "result")]
public Result result { get; set; }
}
[DataContract]
public class Result
{
[DataMember(Name = "lookups")]
public List<Item> lookups { get; set; }
}
[DataContract]
public class Item
{
[DataMember(Name = "groups")]
public List<Dictionary<string, object>> groups { get; set; }
}
为清晰起见,我简化了JSON和代码示例.
我包含了代码aspx以简化再现.
Test.aspx文件
<%@ Page Language="C#" AutoEventWireup="true" CodeFile="Test.aspx.cs" Inherits="Test" %>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head runat="server">
<title></title>
</head>
<body>
<form id="form1" runat="server">
<div>
<code>
<%=response %>
</code></div>
</form>
</body>
</html>
test.aspx.cs
using System;
using System.Collections.Generic;
using System.IO;
using System.Linq;
using System.Web;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Runtime.Serialization;
using Newtonsoft.Json;
using Newtonsoft.Json.Linq;
using NLog;
public partial class Test : System.Web.UI.Page
{
public string response = string.Empty;
public static string cacheDirPath = HttpRuntime.AppDomainAppPath + "cache\\";
private static Logger log = LogManager.GetLogger("productFeed");
protected void Page_Load(object sender, EventArgs e)
{
response = readDataFromFile(cacheDirPath + "test2.json");
Response masheryResult = JsonConvert.DeserializeObject<Response>(response);
}
private string readDataFromFile(string filePath)
{
string JSONData = string.Empty;
try
{
StreamReader myFile = new StreamReader(filePath);
JSONData = myFile.ReadToEnd();
myFile.Close();
}
catch (Exception e)
{
log.Warn(e.Message);
}
return JSONData;
}
}
// response
[DataContract]
public class Response
{
[DataMember(Name = "result")]
public Result result { get; set; }
}
[DataContract]
public class Result
{
[DataMember(Name = "lookups")]
public List<Item> lookups { get; set; }
}
[DataContract]
public class Item
{
[DataMember(Name = "groups")]
public List<Dictionary<string, object>> groups { get; set; }
}
Con*_*des 14
"flags1"对象中的两个属性都被命名为"string",您无法定义属性两次.
编辑:似乎,至少在最新的nuget版本中,JObject.Parse跳过错误并正确解析数据!我希望你能为你做这件事.
这是一个如何做到这一点的例子:
Response result = JObject.Parse(unfilteredJSONData).ToObject<Response>();
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