如何在django-tastypie上传带有POST请求的文件？

Question

可能重复:
Django-tastypie:POST中文件上传的任何示例？

我目前正在对我的API执行cURL POST请求

curl --dump-header - -H "Content-Type: application/json" -X POST --data '{"username":"theusername", "api_key":"anapikey", "video_title":"a title", "video_description":"the description"}' http://localhost:8000/api/v1/video/ 

但现在我需要能够将视频文件添加到上传中.我一直在寻找有关使用Tastypie上传文件的几个小时,我还没有想出一个坚实的回复.我需要添加Base64编码吗？如果是这样的话？在我通过POST请求上传文件后如何访问该文件？只是正常的request.FILES动作？我不是要将文件保存到数据库,只是获取文件的路径.

#Models.py
class Video(models.Model):
    video_uploader = models.ForeignKey(User)
    video_path = models.CharField(max_length=128)
    video_views = models.IntegerField(default=0)
    upload_date = models.DateTimeField(auto_now_add=True)
    video_description = models.CharField(max_length=860)
    video_title = models.SlugField()

我对如何为Tastypie实现文件上传系统感到非常困惑,所以任何帮助都将非常感激.谢谢!

Answer 1

这是通过方法来上传文件MultiPart通过django-tastypie.

Models.py

class Video(models.Model):
    video_uploader = models.ForeignKey(User)
    video = models.FileField(_('Video'), upload_to='path_to_folder/') # save file to server
    video_views = models.IntegerField(default=0)
    upload_date = models.DateTimeField(auto_now_add=True)
    video_description = models.CharField(max_length=860)
    video_title = models.SlugField()

Api.py

class MultipartResource(object):
    def deserialize(self, request, data, format=None):
        if not format:
            format = request.META.get('CONTENT_TYPE', 'application/json')
        if format == 'application/x-www-form-urlencoded':
            return request.POST
        if format.startswith('multipart'):
            data = request.POST.copy()
            data.update(request.FILES)
            return data
        return super(MultipartResource, self).deserialize(request, data, format)

class VideoResource(MultipartResource, ModelResource):
   """
   Inherit this Resource class to `MultipartResource` Class
   """
   # Assuming you know what to write here 
   ...

然后通过 CURL

curl -H "Authorization: ApiKey username:api_key" -F "video=/path_to_video/video.mp3" -F "video_title=video title" http://localhost:8000/api/v1/video/ -v