asp.net mvc 4与jquery-file-upload Request.Files.Count始终为0

Question

我目前正在使用asp.net mvc 4,并使用jquery-file-upload来上传图片,如果我这样初始化:

        $('#fileupload').fileupload();

        $('#fileupload').fileupload('option', {
            //url: '/Admin/News/Create',
            maxFileSize: 500000000,
            acceptFileTypes: /(\.|\/)(gif|jpe?g|png)$/i,
            maxNumberOfFiles: 1,
            resizeMaxWidth: 1920,
            resizeMaxHeight: 1200,
        });

当选择图像文件时,图像可以在borwser中预览,但在mvc Action Request.Files.Count为0时,表示没有上传文件.如果我这样初始化:

        //$('#fileupload').fileupload();

        $('#fileupload').fileupload('option', {
            //url: '/Admin/News/Create',
            maxFileSize: 500000000,
            acceptFileTypes: /(\.|\/)(gif|jpe?g|png)$/i,
            maxNumberOfFiles: 1,
            resizeMaxWidth: 1920,
            resizeMaxHeight: 1200,
        });

我无法预览图像,但mvc Action获取文件,有谁知道为什么？控制器的邮政编码:

    [HttpPost]
    [ValidateInput(false)]
    public ActionResult Create(NewsViewModel model, FormCollection form)
    {
        if (ModelState.IsValid)
        {
            //....

            // upload image
            foreach (string file in Request.Files)
            {
                HttpPostedFileBase hpf = Request.Files[file] as HttpPostedFileBase;
                if (hpf.ContentLength == 0)
                    continue;
                string path = Path.Combine(Server.MapPath("~/Uploads/News/"),GUID.NewGuid()+ Path.GetExtension(hpf.FileName));
                hpf.SaveAs(path);

                data.ImagePath = path;
                _iNewsService.UpdateNews(data);
            }
        }           
    }

Answer 1

我遇到了同样的问题，用以下方法解决了它：

    [HttpPost]
    [ValidateInput(false)]
    public ActionResult Create(NewsViewModel model, FormCollection form)
    {                  
            var length = Request.ContentLength;
            var bytes = new byte[length];
            Request.InputStream.Read(bytes, 0, length); 

            //or for creating image from stream 

            Bitmap bmp = new Bitmap(Bitmap.FromStream(InputStream));
            bmp.Save("some path");  

   }

希望这能有所帮助。