在Octave中使用textscan()...如何正确格式化?

jml*_*jml 0 formatting file-io numeric octave

我在磁盘上有一个数据集,正在逐行读取,我想将数据列之一转换为浮点向量(范围为0-23.99999)(当天)。

数据如下所示:

2010/01/01,00:00:00.979131, 27.4485,  51.9362, 14.8,  6
2010/01/01,00:00:01.021977, 27.5149,  51.9375, 16.0,  6
2010/01/01,00:00:01.074032, 27.4797,  51.9446, 14.5, 10
2010/01/01,00:00:01.663689, 25.8441,-152.8141, 14.6,  6
2010/01/01,00:00:01.639541, 25.8744,-152.6122,  1.5,  5
2010/01/01,00:00:02.232099, -2.2447,  11.5023, 18.8,  6
2010/01/01,00:00:02.256351, -0.8135,  27.3139, 17.7,  5
2010/01/01,00:00:02.306734, -2.7797,  28.5109, 26.0,  5
2010/01/01,00:00:02.620765, 25.6656,-154.2029, 26.2,  9
2010/01/01,00:00:02.658495, 25.6698,-154.2157, 23.0,  6
2010/01/01,00:00:02.731266, -5.7106, 126.4517,  3.6,  5
2010/01/01,00:00:02.787495, -5.7138, 126.5210, 24.4,  8
2010/01/01,00:00:02.811636, -3.2453, 124.6919, 21.1,  8
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第2栏(例如00:00:00.979131)很有趣,我想做类似的事情

setenv GNUTERM 'x11';
fid = fopen('myfile.txt', 'r');
m = textscan(fid, '%d%d%d%d/%d%d/%d%d, %d%d:%d%d:%d%f, %f, %f, %f, %d');
mx = m(:, 5); %here, I would expect to grab 14.8, 16.0, etc
my = m(:, 2) / 24.0; %here, all data from timestamp column (00:00:00.979131, for ex)
plot(mx, my);
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问题是我传递给的字符串的textscan数据格式错误。该数字的格式为“ hrs:minutes:seconds”(军事时间)。如何访问/转换var mx或的值my

谢谢,jml

nrz*_*nrz 5

的输出textscan是一个单元数组。如果您在答案中使用命令:

m = textscan(fid, '%d/%d/%d %d:%d:%f %f %f %f %d', 'delimiter', ',');
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然后获得14.9、16.0、14.5的垂直向量:

MyNinthField = m{9};

MyNinthField =
14.8000
16.0000
14.5000
14.6000
 1.5000
18.8000
17.7000
26.0000
26.2000
23.0000
 3.6000
24.4000
21.1000
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然后,获取时间戳(从一天开始算起的秒数):

Hours = double(m{4});
Minutes = double(m{5});
Seconds = m{6};
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对于Seconds double不需要,因为m{6}已经是double。然而,m{4}m{5}都是int32

要获得以秒为单位的一天中的时间,您需要做的是:

TimeOfDayInSeconds = 3600*Hours+60*Minutes+Seconds;

TimeOfDayInSeconds =
0.97913
1.02198
1.07403
1.66369
1.63954
2.23210
2.25635
2.30673
2.62077
2.65849
2.73127
2.78749
2.81164
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如果您不进行从int32到类型的转换double,则Octave会将值截断为整数。但是,MATLAB甚至不允许整数和双精度数组之和。

希望这可以帮助。