如何在Play 2.0框架中为路由编写单独的单元测试？

Question

我的play框架应用程序是scala(而不是Java).我找到了一个页面,描述了如何使用实用程序类play.test.Helpers进行单元测试路由.这个例子是Java,而不是scala.我在scala中编写了测试,但是我收到错误"消息:这不是JavaAction,不能以这种方式调用".

这是我发现的页面,描述了如何在play framework 2.0中测试路由:http: //digitalsanctum.com/2012/05/28/play-framework-2-tutorial-testing/

...这是我试图编写的代码来测试我的应用程序:

package conf
import org.scalatest._
import play.mvc.Result
import play.test.Helpers._

class routeTest extends FunSpec with ShouldMatchers {

  describe("route tests") {
    it("") {
      // routeAndCall() fails.  Message: This is not a JavaAction and can't be invoked this way.
      val result = routeAndCall(fakeRequest(GET, "/"))
      result should not be (null)
    }
  }
}

问题是因为我的行为是Scala而不是Java？我可以通过Scala控制器对我的路线进行单元测试吗

Answer 1

您应该使用play.api.*Scala代码中的导入.play.*是一个Java api.所以你的代码应该是这样的:

package conf

import org.scalatest._
import org.scalatest.matchers._
import play.api._
import play.api.mvc._
import play.api.test.Helpers._
import play.api.test._

class routeTest extends FunSpec with ShouldMatchers {
  describe("route tests") {
    it("GET / should return result") {
      val result = routeAndCall(FakeRequest(GET, "/"))
      result should be ('defined)
    }
  }
}

甚至更好地使用FlatSpec:

package conf

import org.scalatest._
import org.scalatest.matchers._
import play.api._
import play.api.mvc._
import play.api.test.Helpers._
import play.api.test._

class routeTest extends FlatSpec with ShouldMatchers {

  "GET /" should "return result" in {
    val result = routeAndCall(FakeRequest(GET, "/"))
    result should be ('defined)
  }

  it should "return OK" in {
    val Some(result) = routeAndCall(FakeRequest(GET, "/"))
    status(result) should be (OK)
  }

}

此外,routeAndCall不返回null.它返回Option[Result],即Some[Result]或None,因此在这种情况下,空检查不起作用.