在Jackson/Jersey JAVA上使用多个参数JSON和String发布请求

Question

我用Jersey/Jackson创建了一个休息api,效果很好.我想调整我的POST方法以接收除了作为JSON接收的POJO之外的字符串标记.我调整了我的一个方法,如下:

@POST
@Path("/user")
@Consumes(MediaType.APPLICATION_JSON)
public Response createObject(User o, String token) {
    System.out.println("token: " + token);
    String password = Tools.encryptPassword(o.getPassword());
    o.setPassword(password);
    String response = DAL.upsert(o);
    return Response.status(201).entity(response).build();

}

我想调用该方法,但无论出于何种原因,无论我尝试什么,令牌都会打印为null.这是我写的发送帖子请求的客户端代码:

public String update() {

    try {
        com.sun.jersey.api.client.Client daclient = com.sun.jersey.api.client.Client
                .create();
        WebResource webResource = daclient
                .resource("http://localhost:8080/PhizzleAPI/rest/post/user");

        User c = new User(id, client, permission, reseller, type, username,
                password, name, email, active, createddate,
                lastmodifieddate, token, tokentimestamp);
        JSONObject j = new JSONObject(c);
        ObjectMapper mapper = new ObjectMapper();

        String request = mapper.writeValueAsString(c) + "&{''token'':,''"
                + "dog" + "''}";
        System.out.println("request:" + request);
        ClientResponse response = webResource.type("application/json")
                .post(ClientResponse.class, request);
        if (response.getStatus() != 201) {
            throw new RuntimeException("Failed : HTTP error code : "
                    + response.getStatus());
        }

        System.out.println("Output from Server .... \n");
        String output = response.getEntity(String.class);
        setId(UUID.fromString(output));
        System.out.println("output:" + output);
        return "" + output;
    } catch (UniformInterfaceException e) {
        return "failue: " + e.getMessage();
    } catch (ClientHandlerException e) {
        return "failue: " + e.getMessage();
    } catch (Exception e) {
        return "failure: " + e.getMessage();
    }

}

任何帮助将不胜感激.

Answer 1

这不是JAX-RS的工作方式.POST请求的主体将被封送到带注释的资源方法的第一个参数(在这种情况下,进入User参数).你有两个选择来解决这个问题:

1. 创建一个包含User对象和令牌的包装器对象.在客户端和服务器之间来回发送.
2. 将令牌指定为URL上的查询参数,并在服务器端将其作为a访问@QueryParam.
3. 将标记添加为标头参数,并在服务器端将其作为a访问@HeaderParam.

示例 - 选项1

class UserTokenContainer implements Serializable {
    private User user;
    private String token;

    // Constructors, getters/setters
}

示例 - 选项2

客户:

WebResource webResource = client.
    resource("http://localhost:8080/PhizzleAPI/rest/post/user?token=mytoken");

服务器:

@POST
Path("/user")
@Consumes(MediaType.APPLICATION_JSON)
public Response createObject(@QueryParam("token") String token, User o) {
    System.out.println("token: " + token);
    // ...
}

示例 - 选项3

客户:

ClientResponse response = webResource
    .type("application/json")
    .header("Token", token)
    .post(ClientResponse.class, request);

服务器:

@POST
Path("/user")
@Consumes(MediaType.APPLICATION_JSON)
public Response createObject(@HeaderParam("token") String token, User o) {
    System.out.println("token: " + token);
    // ...
}