访问SQL Count字段,其中equals值

Question

我正在为一个客户的桌子工作,他们只希望计算特定的列值我已经采用了一种方式,但它不是他们需要的结果,所以它不在一边.

我有这样的表.(注:不是实际的表)

company_name | type  | ................
com A        | type1 | ................
com A        | type2 | ................
com B        | type1 | ................
com A        | type2 | ................
com A        | type1 | ................
com C        | type1 | ................
com C        | type2 | ................
com A        | type1 | ................

所以在类型列中如此,尽管其中有列,它们根本不需要计数

所需的表格如下所示

company_name | Type1 | Type2 | ..........
com A        |   3   |   2   | ..........
com B        |   1   |   0   | ..........
com C        |   1   |   1   | ..........

到目前为止我得到的是:

company_name | Type  | count | ..........
com A        | type1 |   3   | ..........
com A        | type2 |   2   | ..........
com B        | type1 |   1   | ..........
com C        | type1 |   1   | ..........
com C        | type2 |   1   | ..........

请帮助我一直在抓我的头骨.

Answer 1

试试这个:

SELECT
  company_name,
  SUM(IIF(Type = 'type1', 1, 0)) AS Type1,
  SUM(IIF(Type = 'type2', 1, 0)) AS Type2,
  SUM(IIF(Type = 'type3', 1, 0)) AS Type3
FROM table
GROUP BY company_name;

更新

在MySQL中,您可以使用IF语句而不是Access IIF,也可以在没有IF或CASE因为MySQL隐式转换的情况下编写它:

SELECT Promoter, 
  Sum(NoticeType = 'VARIATION')       AS 'Variation', 
  Sum(NoticeType = 'TWO HOURS AFTER') AS 'Two Hours After', 
  Sum(NoticeType = 'THREE MONTHS')    AS 'Three Months', 
  Sum(NoticeType = 'THREE DAY')       AS 'Three Day', 
  Sum(NoticeType = 'TEN DAY')         AS 'Ten Day' 
FROM notices 
GROUP BY Promoter;