如何使用get或post方法将用户从视图输入的数据传递到codeigniter Php中的控制器？我现在是codeigniter的新手.谢谢!
AddProduct.php(我的观点)
<body>
<form method="POST" action="SaveProductController"></br></br></br>
<table border='1' align='center'>
<tr>
<td>ID: </td><td><input type="text" name="id"
value="<?php echo $GetProductId->id + 1; ?>" readonly="readonly"></td>
</tr>
<tr>
<td>Description: </td><td><input type="text" name="description"></td>
</tr>
<tr>
<td></td><td><input type="submit" name="addProduct" value="Add Product"><td>
</tr>
</table>
</form>
</body>
SaveProductController .php(我的控制器)
class SaveProductController extends CI_Controller{
function index($description){
$this->load->model('ProductDao');
$data['id'] = $this->id;
$data['description'] = $this->description;
print_r($data);
//$this->ProductDao->saveProduct();
}
}
ProductDao.php
function saveProduct() {
$data = array(
'id' => $this->input->xss_clean($this->input->post('id')),
'description' => $this->input->xss_clean($this->input->post('description')),
'price' => $this->input->xss_clean($this->input->post('price')),
'size' => $this->input->xss_clean($this->input->post('size')),
'aisle' => $this->input->xss_clean($this->input->post('aisle')),
);
$query = $this->db->insert('mytable', $data);
}
<body>
<form method="POST" action="<?php echo $this->base_url();?>/controllername/methodname"></br></br></br>
<table border='1' align='center'>
<tr>
<td>ID: </td><td><input type="text" name="id"
value="<?php echo $GetProductId->id + 1; ?>" readonly="readonly"></td>
</tr>
<tr>
<td>Description: </td><td><input type="text" name="description"></td>
</tr>
<tr>
<td></td><td><input type="submit" name="addProduct" value="Add Product"><td>
</tr>
</table>
</form>
</body>
观察行动的变化
并在你的comtroller指定的方法获取值,如下所示
$id=$this->input->post('id')
$idescription=$this->input->post('description')
然后将这些发送到模型并执行您想要的任何操作
加载url helper库使其$this->baseurl()工作使用其他明智的硬代码localhost/path...