TypeError:zip参数#1必须支持迭代

Question

for k,v in targets.iteritems():
    price= str(v['stockprice'])

    Bids = str(u''.join(v['OtherBids']))
    Bids = Bids.split(',')

    # create a list of unique bids by ranking
    for a, b in zip(float(price), Bids):
        try:
            del b[next(i for i, e in enumerate(b) if format(e, '.4f')  == a)]
        except StopIteration:
            pass

我从我的字典中提取数据,但似乎所有这些都是unicode.我怎么能摆脱unicode废话？

Answer 1

我认为你的代码是给你错误信息,TypeError:zip参数#1必须支持迭代.由于表达式,您收到此错误zip(float(price), Bids).此简化代码演示了错误:

>>> price = str(u'12.3456')
>>> bids = ['1.0', '2.0']
>>> zip(float(price), bids)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: zip argument #1 must support iteration

在Python的2.X zip()的内置库函数要求其所有参数是iterables.float(price)不是可迭代的.

如果要将元组float(price)与数组的每个元素组合在一起Bids,可以itertools.repeat()在第一个参数表达式中使用.

>>> import itertools
>>> price = str(u'12.3456')
>>> bids = ['1.0', '2.0']
>>> zip(itertools.repeat(float(price),len(bids)), bids)
[(12.345599999999999, '1.0'), (12.345599999999999, '2.0')]

我没有看到你使用Unicode数据类型与TypeError.