Fil*_*lly 16
这是我在问题中找到的解决方案的一般示例:
在forms.py文件中:
class MyForm(ModelForm):
class Meta:
model = MyModel
fields = ('description',)
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在views.py文件中:
from django.core.paginator import Paginator, EmptyPage, PageNotAnInteger
FormSet = modelformset_factory(MyModel, form=MyForm, extra=0)
if request.method == 'POST':
formset = FormSet(request.POST, request.FILES)
# Your validation and rest of the 'POST' code
else:
query = MyModel.objects.filter(condition)
paginator = Paginator(query, 10) # Show 10 forms per page
page = request.GET.get('page')
try:
objects = paginator.page(page)
except PageNotAnInteger:
objects = paginator.page(1)
except EmptyPage:
objects = paginator.page(paginator.num_pages)
page_query = query.filter(id__in=[object.id for object in objects])
formset = FormSet(queryset=page_query)
context = {'objects': objects, 'formset': formset}
return render_to_response('template.html', context,
context_instance=RequestContext(request))
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您需要使用当前页面中的对象创建formset,否则,当您尝试formset = FormSet(request.POST, request.FILES)在POST方法中执行时,Django会引发MultiValueDictKeyError错误.
在template.html文件中:
{% if objects %}
<form action="" method="post">
{% csrf_token %}
{{ formset.management_form }}
{% for form in formset.forms %}
{{ form.id }}
<!-- Display each form -->
{{ form.as_p }}
{% endfor %}
<input type="submit" value="Save" />
</form>
<div class="pagination">
<span class="step-links">
{% if objects.has_previous %}
<a href="?page={{ objects.previous_page_number }}">Previous</a>
{% endif %}
<span class="current">
Page {{ objects.number }} of {{ objects.paginator.num_pages }}
</span>
{% if objects.has_next %}
<a href="?page={{ objects.next_page_number }}">next</a>
{% endif %}
</span>
</div>
{% else %}
<p>There are no objects.</p>
{% endif %}
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