使用谷歌地图,PHP和MySQL从A点到B点的距离

Question

谁能请帮忙.我只需要一个简单的脚本.我有一张表格张贴到另一页.两个表格是:

fromaddress和toaddress

我唯一需要的是一个脚本,它显示了以km为单位的距离以及使用谷歌地图所需的时间.我找到了几十个脚本,但我无法使用它.地图已经存在,这个代码看起来很完美.

<script type="text/javascript" src="//maps.googleapis.com/maps/api/js?key=AIzaSyDdDwV6_l5n2bS3gM6NBCla3RFLtIFc_HE&sensor=false"></script><script type="text/javascript">
    var directionDisplay;
    var directionsService = new google.maps.DirectionsService();
    var map;

    function initialize() {
        directionsDisplay = new google.maps.DirectionsRenderer();
        var myOptions = {
            zoom: 8,
            mapTypeId: google.maps.MapTypeId.ROADMAP,
        }
        map = new google.maps.Map(document.getElementById("map_canvas"), myOptions);
        directionsDisplay.setMap(map);

        var start = "<? echo $_POST[fromaddress]; ?>";
        var end = "<? echo $_POST[toaddress]; ?>";
        var request = {
            origin:start, 
            destination:end,
            travelMode: google.maps.DirectionsTravelMode.DRIVING
        };
        directionsService.route(request, function(response, status) {
            if (status == google.maps.DirectionsStatus.OK) {
                directionsDisplay.setDirections(response);
            }
        });

    }

    $(document).ready(function(){
        initialize();
    });        
</script>

但是我如何显示距离和时间.最好的选择是使用php值来获取它:

$distance = some-code;
$time = some-code-too;

非常感谢您的帮助.

Answer 1

您需要使用不同的API.首先,不要使用JS而是使用PHP,这里的代码片段应该适合你;)

$from = "Wi?ckowskiego 72, ?ód?";
$to = "Gazowa 1, ?ód?";

$from = urlencode($from);
$to = urlencode($to);

$data = file_get_contents("http://maps.googleapis.com/maps/api/distancematrix/json?origins=$from&destinations=$to&language=en-EN&sensor=false");
$data = json_decode($data);

$time = 0;
$distance = 0;

foreach($data->rows[0]->elements as $road) {
    $time += $road->duration->value;
    $distance += $road->distance->value;
}

echo "To: ".$data->destination_addresses[0];
echo "<br/>";
echo "From: ".$data->origin_addresses[0];
echo "<br/>";
echo "Time: ".$time." seconds";
echo "<br/>";
echo "Distance: ".$distance." meters";

输出:

To: Gazowa 1, 91-076 ?ód?, Poland
From: Wi?ckowskiego 72, ?ód?, Poland
Time: 206 seconds
Distance: 1488 meters