从AVPlayer对象访问URL？

Question

有没有办法从已使用URL初始化的AVPlayer对象访问URL,如下所示:

NSURL *url = [NSURL URLWithString: @"http://www.example.org/audio"];
self.player = [AVPlayer playerWithURL: url];

Answer 1

一个人AVPlayer玩AVPlayerItem.AVPlayerItems由类的对象支持AVAsset.当您使用它的playerWithURL:方法时,AVPlayer它会自动创建AVPlayerItem由作为AVAssetnamed 的子类的资产支持AVURLAsset.AVURLAsset有URL房产.

所以,是的,在你提供的情况下,你可以NSURL很容易地获得当前播放的项目.这是一个如何执行此操作的示例函数:

-(NSURL *)urlOfCurrentlyPlayingInPlayer:(AVPlayer *)player{
    // get current asset
    AVAsset *currentPlayerAsset = player.currentItem.asset;
    // make sure the current asset is an AVURLAsset
    if (![currentPlayerAsset isKindOfClass:AVURLAsset.class]) return nil;
    // return the NSURL
    return [(AVURLAsset *)currentPlayerAsset URL];
}

不是一个快速的专家,但它似乎可以更迅速地完成.

func urlOfCurrentlyPlayingInPlayer(player : AVPlayer) -> URL? {
    return ((player.currentItem?.asset) as? AVURLAsset)?.url
}

Answer 2

Swift 3的解决方案

func getVideoUrl() -> URL? {
    let asset = self.player?.currentItem?.asset
    if asset == nil {
        return nil
    }
    if let urlAsset = asset as? AVURLAsset {
        return urlAsset.url
    }
    return nil
}

Answer 3

Oneliner迅捷4.1

let url: URL? = (player?.currentItem?.asset as? AVURLAsset)?.url

Answer 4

AVPlayerItem 扩展基于@eonist答案。

扩展 AVPlayerItem {
    var url: 网址？{
        返回（资产为？AVURLAsset）？.url
    }
}