我知道Java中的int范围应该是-2 ^ 31到2 ^ 31-1.但是当我用20运行这段代码片段时:
public class Factorial {
public int factorial(int n) {
int fac=1;
for (int i=1; i<=n; i++) {
fac *= i;
System.out.println("Factorial of " + i + " is: " + fac);
}
return fac;
}
}
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输出:
Factorial of 1 is: 1
Factorial of 2 is: 2
Factorial of 3 is: 6
Factorial of 4 is: 24
Factorial of 5 is: 120
Factorial of 6 is: 720
Factorial of 7 is: 5040
Factorial of 8 is: 40320
Factorial of 9 is: 362880
Factorial of 10 is: 3628800
Factorial of 11 is: 39916800
Factorial of 12 is: 479001600
Factorial of 13 is: 1932053504
Factorial of 14 is: 1278945280
Factorial of 15 is: 2004310016
Factorial of 16 is: 2004189184
Factorial of 17 is: -288522240
Factorial of 18 is: -898433024
Factorial of 19 is: 109641728
Factorial of 20 is: -2102132736
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它从13开始没有意义.看起来它超出范围并且四处乱窜.怎么了?是因为我正在使用Eclipse吗?
虽然我认为它不相关,但这里是测试代码:
public class TestFac {
public static void main(String[] args) {
int n;
Scanner sc = new Scanner(System.in);
System.out.println("Input num you want to factorial: ");
n = sc.nextInt();
Factorial fac = new Factorial();
fac.factorial(n);
}
}
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Jay*_*Jay 20
在这里我想提一下整数时钟的概念.java中int的最大值和最小值为int MAX_VALUE = 2147483647 int MIN_VALUE = -2147483648
请检查以下结果
int a = 2147483645;
for(int i=0;i<10;i++) {
System.out.println("a:"+ a++);
}
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输出:
a:2147483645
a:2147483646
a:2147483647
a:-2147483648
a:-2147483647
a:-2147483646
a:-2147483645
a:-2147483644
a:-2147483643
a:-2147483642
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它表明当你超出+ ve整数范围的限制时,下一个值再次从其负起始值开始.
-2147483648, <-----------------
-2147483647, |
-2147483646, |
. |
. |
. | (next value will go back in -ve range)
0, |
+1, |
+2, |
+3, |
. |
. |
., |
+2147483645, |
+2147483646, |
+2147483647 ---------------------
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如果计算阶乘13,则为6227020800.此值超出java的int范围.所以新的价值将是
6227020800
- 2147483647 (+ve max value)
-----------------
Value = 4079537153
- 2147483648 (-ve max value)
-----------------
value = 1932053505
- 1 (for zero in between -ve to +ve value)
----------------
Answer = 1932053504
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所以,在你的答案13中的阶乘即将到来1932053504.这就是整数时钟的工作原理.
您可以使用long数据类型而不是整数来实现您的目的.您可以在此处发布任何疑问.