如何在MySQL中按年和月分组

Ben*_*Ben 19 mysql group-by

我想从源表中测量ID和ATTRIBUTE的计数,并显示如下"所需报告"中所示的数据.我正在使用MySQL.

资源:

ID  |  DATE        |  ATTRIBUTE
--------------------------------
1   |  2012-01-14  |   XYZ
2   |  2012-03-14  |   
3   |  2012-03-15  |   XYZ
4   |  2012-04-24  |   ABC
5   |  2012-04-10  |   
6   |  2012-05-11  |   ABC
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期望的报告:

属性数

   YEAR | JAN | FEB | MAR | APR | MAY | JUN | JUL | AUG | SEP | OCT | NOV | DEC
   ---------------------------------------------------------------------------
   2010 |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0 
   2011 |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0 
   2012 |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0 
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ID的数量

   YEAR | JAN | FEB | MAR | APR | MAY | JUN | JUL | AUG | SEP | OCT | NOV | DEC
   ---------------------------------------------------------------------------
   2010 |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0 
   2011 |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0 
   2012 |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0 
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完成百分比(属性计数/ ID计数)

   YEAR | JAN | FEB | MAR | APR | MAY | JUN | JUL | AUG | SEP | OCT | NOV | DEC
   ---------------------------------------------------------------------------
   2010 |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0 
   2011 |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0 
   2012 |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0 
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这是我到目前为止的代码.谢谢!另外请记住,我需要从数据中的日期字段中提取月份,但不确定如何.谢谢.

SELECT YEAR(document_filing_date),MONTH(document_filing_date),COUNT(aif_id)
FROM (a_aif_remaining)
GROUP BY YEAR(document_filing_date),MONTH(document_filing_date);
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建议的答案不起作用!! 不知道为什么,这是我得到的错误:

"#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ' COUNT(CASE WHEN MONTH(document_filing_date) = 1 THEN aif_id END) AS Jan, CO' at line 1"

SELECT YEAR(document_filing_date,
  COUNT(CASE WHEN MONTH(document_filing_date) = 1 THEN aif_id END) AS Jan,
  COUNT(CASE WHEN MONTH(document_filing_date) = 2 THEN aif_id END) AS Feb,
  COUNT(CASE WHEN MONTH(document_filing_date) = 3 THEN aif_id END) AS Mar,
  COUNT(CASE WHEN MONTH(document_filing_date) = 4 THEN aif_id END) AS Apr,
  COUNT(CASE WHEN MONTH(document_filing_date) = 5 THEN aif_id END) AS May,
  COUNT(CASE WHEN MONTH(document_filing_date) = 6 THEN aif_id END) AS Jun,
  COUNT(CASE WHEN MONTH(document_filing_date) = 7 THEN aif_id END) AS Jul,
  COUNT(CASE WHEN MONTH(document_filing_date) = 8 THEN aif_id END) AS Aug,
  COUNT(CASE WHEN MONTH(document_filing_date) = 9 THEN aif_id END) AS Sep,
  COUNT(CASE WHEN MONTH(document_filing_date) = 10 THEN aif_id END) AS Oct,
  COUNT(CASE WHEN MONTH(document_filing_date) = 11 THEN aif_id END) AS Nov,
  COUNT(CASE WHEN MONTH(document_filing_date) = 12 THEN aif_id END) AS Dec,
FROM a_aif_remaining
GROUP BY YEAR(document_filing_date);
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fth*_*lla 39

此查询将计算所有行,并且还将仅计算Attribute非空行,按行分列年份和月份:

SELECT
  Year(`date`),
  Month(`date`),
  Count(*) As Total_Rows,
  Count(`Attribute`) As Rows_With_Attribute
FROM your_table
GROUP BY Year(`date`), Month(`date`)
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(这是因为Count(*)计算所有行,Count(Attibute)计算Attribute不为null的所有行)

如果您需要PIVOT中的表,则可以使用它来仅计算Attribute不为null的行:

SELECT
  Year(`date`),
  Count(case when month(`date`)=1 then `Attribute` end) As Jan,
  Count(case when month(`date`)=2 then `Attribute` end) As Feb,
  Count(case when month(`date`)=3 then `Attribute` end) As Mar,
  ...
FROM your_table
GROUP BY Year(`date`)
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这要计算所有行:

SELECT
  Year(`date`),
  Count(case when month(`date`)=1 then id end) As Jan,
  Count(case when month(`date`)=2 then id end) As Feb,
  Count(case when month(`date`)=3 then id end) As Mar,
  ...
FROM your_table
GROUP BY Year(`date`)
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(或者,不是计算id,你可以像kander的回答一样使用Sum(Month(日期)=1)).当然,您可以将两个查询组合到此:

SELECT
  Year(`date`),
  Count(case when month(`date`)=1 then id end) As Jan_Tot,
  Count(case when month(`date`)=1 then `Attribute` end) As Jan_Attr,
  Count(case when month(`date`)=2 then id end) As Feb_Tot,
  Count(case when month(`date`)=2 then `Attribute` end) As Feb_Attr,
  Count(case when month(`date`)=3 then id end) As Mar_Tot,
  Count(case when month(`date`)=3 then `Attribute` end) As Mar_Attr,
  ...
FROM your_table
GROUP BY Year(`date`)
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  • 如果month = 1,case将返回属性,否则它将返回null,并且如果需要使用id计算所有行的替换属性,则不会计算null值 (2认同)