我在哪里标记lambda表达式异步？

Question

我有这个代码:

private async void ContextMenuForGroupRightTapped(object sender, RightTappedRoutedEventArgs args)
{
    CheckBox ckbx = null;
    if (sender is CheckBox)
    {
        ckbx = sender as CheckBox;
    }
    if (null == ckbx)
    {
        return;
    }
    string groupName = ckbx.Content.ToString();

    var contextMenu = new PopupMenu();

    // Add a command to edit the current Group
    contextMenu.Commands.Add(new UICommand("Edit this Group", (contextMenuCmd) =>
    {
        Frame.Navigate(typeof(LocationGroupCreator), groupName);
    }));

    // Add a command to delete the current Group
    contextMenu.Commands.Add(new UICommand("Delete this Group", (contextMenuCmd) =>
    {
        SQLiteUtils slu = new SQLiteUtils();
        slu.DeleteGroupAsync(groupName); // this line raises Resharper's hackles, but appending await raises err msg. Where should the "async" be?
    }));

    // Show the context menu at the position the image was right-clicked
    await contextMenu.ShowAsync(args.GetPosition(this));
}

...... Resharper的检查抱怨说," 因为没有等待这个呼叫,所以当呼叫完成之前,当前方法的执行仍在继续.考虑将'await'运算符应用于呼叫结果 "(在线路上评论).

所以,我预先"等待"它,但当然,我需要在某处添加"异步" - 但在哪里？

Answer 1

要标记lambda异步,只需async在其参数列表之前添加前缀:

// Add a command to delete the current Group
contextMenu.Commands.Add(new UICommand("Delete this Group", async (contextMenuCmd) =>
{
    SQLiteUtils slu = new SQLiteUtils();
    await slu.DeleteGroupAsync(groupName);
}));

Answer 2

对于使用匿名表达式的人：

await Task.Run(async () =>
{
   SQLLiteUtils slu = new SQLiteUtils();
   await slu.DeleteGroupAsync(groupname);
});

Answer 3

如果您使用 LINQ 方法语法，请在参数之前应用 async 关键字：

 list.Select(async x =>
            {
                await SomeMethod(x);
                return true;
            });