在网页上的文本框中键入时删除任何空格

Question

当我打字时,我怎么能在移动时删除输入文本框的空格？

Answer 1

$(function() {
  var txt = $("#myTextbox");
  var func = function() {
    txt.val(txt.val().replace(/\s/g, ''));
  }
  txt.keyup(func).blur(func);
});

你必须另外处理blur事件,因为用户可以使用上下文菜单粘贴;)

Answer 2

关于正则表达式对此任务的缓慢/不良的荒谬需要进行测试.这可能不是最准确的基准,但它可以说明我的观点.

// Modified roosteronacid's example to consider all whitespace characters
function sanitizer(s) {
    var a = s.split(""),
        i = a.length,
        r = "";

    while (i) {
        i--;
        if (a[i] !== " " || a[i] !== "\t" || a[i] !== "\r" || a[i] !== "\n" || a[i] !== "\f" || a[i] !== "\v") {
            r += a[i];
        }
    }

    return r;
}

// Regular expression method wrapped in a function to incur the same overhead
function regexp(s) {
  return s.replace(/\s+/g, '');
}

var iterations = 10000;
// 1024 characters or good meausure
var text = "Lorem ipsum dolor sit amet, consectetur adipiscing elit. Mauris luctus tristique ante, ac suscipit tortor consequat at. Fusce id tortor quis felis faucibus dignissim. Pellentesque viverra pellentesque eros, ac sagittis quam cursus a. Nullam commodo mauris eget nisi luctus vitae ultricies leo volutpat. Morbi quis quam id elit accumsan semper. Praesent aliquam aliquam tortor vel vulputate. Nulla adipiscing ipsum vitae est luctus imperdiet. Suspendisse potenti. Vestibulum ante ipsum primis in faucibus orci luctus et ultrices posuere cubilia Curae; Vivamus at urna ut leo ornare commodo. Quisque eros dolor, adipiscing quis malesuada quis, molestie nec lectus. Quisque et odio nibh. Integer mattis tincidunt ligula, eu scelerisque erat posuere non. Sed ipsum quam, fringilla id porttitor ac, placerat quis nunc. Praesent sodales euismod ultricies. In porta magna metus. Morbi risus risus, hendrerit sit amet ultrices eu, interdum placerat massa. Nunc at leo dui. Morbi eu nunc mi, at ullamcorper felis. Duis et metus metus. ";

var s = new Date();
for ( var i=0; i<iterations; ++i ) {
  sanitizer(text);
}

console.log((new Date()).getTime() - s.getTime());

var s = new Date();
for ( var i=0; i<iterations; ++i ) {
  regexp(text);
}

console.log((new Date()).getTime() - s.getTime());

8次执行的结果:

# Initial times
sanitizer: 5137, 8927, 8817, 5136, 8927, 5132, 8807, 8804
regexp:    1275, 1271, 1480, 1278, 1274, 1308, 1270, 1270

# Dropped highest and lowest values
sanitizer: 5137, 8817, 5136, 8927, 8807, 8804
regexp:    1275, 1271, 1278, 1274, 1308, 1270

# Averages
sanitizer: (5137 + 8817 + 5136 + 8927 + 8807 + 8804) / 6 = 7604.66667
regexp:    (1275 + 1271 + 1278 + 1274 + 1308 + 1270) / 6 = 1279.33333

结果使用正则表达式快594%.

请参阅Josh Stodola的实施答案.

编辑:我注意到roosteronacid的方法已经改变; 但是,使用r数组会使它更慢.