saj*_*aha 17
如果你只有两个地址,首先尝试通过GEOCODING获得lat lan ,然后有很多方法来获得它们之间的距离.
要么
如果你不需要地理编码并想要一个CS解决方案试试这个:
public int getDistance(string origin, string destination)
{
System.Threading.Thread.Sleep(1000);
int distance = 0;
//string from = origin.Text;
//string to = destination.Text;
string url = "http://maps.googleapis.com/maps/api/directions/json?origin=" + origin + "&destination=" + destination + "&sensor=false";
string requesturl = url;
//string requesturl = @"http://maps.googleapis.com/maps/api/directions/json?origin=" + from + "&alternatives=false&units=imperial&destination=" + to + "&sensor=false";
string content = fileGetContents(requesturl);
JObject o = JObject.Parse(content);
try
{
distance = (int)o.SelectToken("routes[0].legs[0].distance.value");
return distance;
}
catch
{
return distance;
}
return distance;
//ResultingDistance.Text = distance;
}
protected string fileGetContents(string fileName)
{
string sContents = string.Empty;
string me = string.Empty;
try
{
if (fileName.ToLower().IndexOf("http:") > -1)
{
System.Net.WebClient wc = new System.Net.WebClient();
byte[] response = wc.DownloadData(fileName);
sContents = System.Text.Encoding.ASCII.GetString(response);
}
else
{
System.IO.StreamReader sr = new System.IO.StreamReader(fileName);
sContents = sr.ReadToEnd();
sr.Close();
}
}
catch { sContents = "unable to connect to server "; }
return sContents;
}
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要么
如果你不想搞乱谷歌并且只需要AIR DISTANCE,试试这个:
public decimal calcDistance(decimal latA, decimal longA, decimal latB, decimal longB)
{
double theDistance = (Math.Sin(DegreesToRadians(latA)) *
Math.Sin(DegreesToRadians(latB)) +
Math.Cos(DegreesToRadians(latA)) *
Math.Cos(DegreesToRadians(latB)) *
Math.Cos(DegreesToRadians(longA - longB)));
return Convert.ToDecimal((RadiansToDegrees(Math.Acos(theDistance)))) * 69.09M * 1.6093M;
}
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注意:自2018年6月11日起,由于Google已停用对Maps API的无密钥访问权限,此方法将无法运行.如果您希望使用此方法,则必须注册其云平台并启用结算功能.