ave*_*joe 6 xml postgresql select one-to-many
我的架构中有多个关系.例如,一个包有许多任务组,任务组又有许多任务.所有表都通过多个表链接在一起,例如包含主键和taskgroup的主键.(我知道这不是严格需要的,因为XML是一对多的,但我想不出更好的结构).
是否可以将查询结果作为XML来反映一对多结构?所以,结果应该是这样的:
<package id=1>
<taskgroup id=1>
<task id=1>
<task id=2>
</taskgroup>
<taskgroup id=2>
<task id=3>
</taskgroup>
</package>
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通过使用XMLELEMENT()
和XMLATTRIBUTE()
函数来获取所有任务,我已经设法获得了我想要的一部分.像这样:
SELECT XMLELEMENT(name task,
XMLATTRIBUTES(p.name as packageName),
XMLELEMENT(name description, t.description),
XMLELEMENT(name tutorial,
XMLELEMENT(name someTaskChild1, t.data1)),
XMLELEMENT(name objectives,
XMLELEMENT(name someTaskChild2, t.data2)),
)
FROM packages p
INNER JOIN package_taskgroup pt ON p.id = pt.package_id
INNER JOIN taskgroups tg on pt.taskgroup_id = tg.id
INNER JOIN taskgroup_task tt on tg.id = tt.taskgroup_id
INNER JOIN tasks t on tt.task_id = t.id
WHERE p.id = somePackageId AND tg.id = someTaskGroupId
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问题是如何将这些任务分组到其父表元素中?
尝试:
SELECT p.id as pack_id,
XMLELEMENT(name taskgroup,
XMLATTRIBUTES(tg.id as id),
XMLAGG(XMLELEMENT(name task,
XMLATTRIBUTES(t.id as id)) as xml_task_group
FROM packages p
JOIN package_taskgroup pt ON p.id = pt.package_id
JOIN taskgroups tg on pt.taskgroup_id = tg.id
JOIN taskgroup_task tt on tg.id = tt.taskgroup_id
JOIN tasks t on tt.task_id = t.id
WHERE p.id = somePackageId
GROUP BY p.id, tg.id
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这将为p.id
您指定所有任务组.
然后:
SELECT XMLELEMENT(name package,
XMLATTRIBUTES(pack_id as id),
XMLAGG(xml_task_group))
FROM (previous SELECT here)
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这将为您提供您指定的结构.
加入选择将如下所示:
SELECT XMLELEMENT(name package,
XMLATTRIBUTES(pack_id as id),
XMLAGG(xml_task_group))
FROM (SELECT p.id as pack_id,
XMLELEMENT(name taskgroup,
XMLATTRIBUTES(tg.id as id),
XMLAGG(XMLELEMENT(name task,
XMLATTRIBUTES(t.id as id)
))) as xml_task_group
FROM packages p
JOIN package_taskgroup pt ON p.id = pt.package_id
JOIN taskgroups tg on pt.taskgroup_id = tg.id
JOIN taskgroup_task tt on tg.id = tt.taskgroup_id
JOIN tasks t on tt.task_id = t.id
WHERE p.id = somePackageId
GROUP BY p.id, tg.id) t
GROUP BY pack_id
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我只是复制FROM
了第二个的第一个select into 子句.