如何在dicts列表中查找公共密钥并按值对其进行排序？

Question

我想创建一个finalDic,它包含公共键和值的总和

myDic = [{2:1, 3:1, 5:2}, {3:4, 6:4, 2:3}, {2:5, 3:6}, ...]

首先找到共同的密钥

commonkey = [{2:1, 3:1}, {2:3, 3:4}, {2:5, 3:6}]

然后按它们的值求和并排序

finalDic= {3:11, 2,9}

我试过这个,甚至没有关闭我想要的东西

import collections

myDic = [{2:1, 3:1, 5:2}, {3:4, 6:4, 2:3}, {2:5, 3:6}]

def commonKey(x):
    i=0
    allKeys = []
    while i<len(x):
        for key in x[0].keys():
            allKeys.append(key)
        i=i+1
    commonKeys = collections.Counter(allKeys)
    commonKeys = [i for i in commonKeys if commonKeys[i]>len(x)-1]
    return commonKeys

print commonKey(myDic)

谢谢

Answer 1

这是我如何做到的:

my_dict = [{2:1, 3:1, 5:2}, {3:4, 6:4, 2:3}, {2:5, 3:6}]

# Finds the common keys
common_keys = set.intersection(*map(set, my_dict))

# Makes a new dict with only those keys and sums the values into another dict
summed_dict = {key: sum(d[key] for d in my_dict) for key in common_keys}

或者作为一个疯狂的单行:

{k: sum(d[k] for d in my_dict) for k in reduce(set.intersection, map(set, my_dict))}