use*_*451 5 sql exists subquery
我有4张桌子
users
| id |Username|
| 1 | John |
| 2 | Mike |
| 3 | Alex |
user_contacts
| user_id |contact_id|
| 1 | 2 |
| 1 | 3 |
| 2 | 3 |
contact_groups
| id | Group name |
| 1 | Group 1 |
| 2 | Group 2 |
| 3 | Group 3 |
user_contact_groups
| user_id |contact_group_id|
| 1 | 1 |
| 1 | 2 |
| 3 | 2 |
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id喜欢做的是拉取属于Contact Group 1和3的用户或者用户1的联系人(在表中:user_contacts).下面是代码,但它返回查询为空
SELECT DISTINCT a.* from users as a
WHERE EXISTS (SELECT * FROM user_contacts as b
WHERE b.user_id = 1) OR
(a.id IN (select c.user_id
FROM user_contact_groups as c
WHERE c.contact_group_id IN (1,3)));
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我就是这样做的,应该是最优的:
SELECT DISTINCT u.*
FROM users u
LEFT OUTER JOIN user_contacts c ON u.id = c.contact_id
AND c.user_id = 1
LEFT OUTER JOIN user_contact_groups g ON u.user_id = g.user_id
AND g.contact_group_id IN (1,3)
WHERE c.id IS NOT NULL OR g.id IS NOT NULL
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如果你想使用EXISTS,你当然可以转过来,但查询可能无法使用索引(你可以删除此查询的DISTICT):
SELECT *
FROM users u
WHERE EXISTS
(
SELECT 1
FROM user_contacts c
WHERE c.contact_id = u.id
AND c.user_id = 1
)
OR EXISTS
(
SELECT 1
FROM user_contact_groups g
WHERE g.user_id = u.user_id
AND g.contact_group_id IN (1,3)
)
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我建议做一个EXPLAIN,看看哪个更适合你的RDBMS.