如何计算最接近100的平均数？

Question

我有一个MySQL表格,我从一个游戏中收集了一个数字列表,用户必须点击一个按钮才能接近100.

我以为我会用AVG(),但这显然不会起作用,因为当你有0和200时,它看起来好像你得了一个完美的100.

我需要的是每一轮(有10个)计算距离100这个数字有多远并计算它们.

Example:
User A: 98 + 102 + 102 = 6 (something) Loser!
User B: 95 + 100 + 100 = 5 (something) Winner!

我有什么,但显然有缺陷:

SELECT user_id, AVG(score) AS Average, (100-AVG(score)) AS Difference, 
DATE(playtime) AS Playdate 
FROM playtable
GROUP BY user_id, DATE(playtime) 
ORDER BY Playdate DESC, user_id

Answer 1

这应该做到这一点

SELECT user_id, SUM( ABS(100-score) ) as cumulative_error,
  DATE(playtime) AS Playdate 
FROM playtable
GROUP BY user_id, DATE(playtime) 
ORDER BY Playdate DESC, user_id

cumulative_error将包含累积的差值