Jea*_*agr 6 c# mysql database-connection
我正在尝试使用以下代码连接到我的远程MySQL服务器.你能告诉我我做错了什么,因为用变量替换数据库连接信息似乎没有用.
using MySql.Data.MySqlClient;
string db_Server = "10.0.0.0";
string db_Name = "myDatabase";
string db_User = "myUser";
string db_Pass = "myPassword";
// Connection String
MySqlConnection myConnection = new MySqlConnection("server = {0}; database = {1}; uid = {2}; pwd = {3}", db_server, db_Name, db_User, db_Pass);
Run Code Online (Sandbox Code Playgroud)
作为PHP开发人员,我更喜欢使用上面的代码而不是下面的故意转换:
MySqlConnection myConnection = new MySqlConnection("server=10.0.0.0; database=myDatabase; uid=myUser; pwd=myPassword");
Run Code Online (Sandbox Code Playgroud)
但正如你在这张图片中看到的那样,我得到了很多红色的曲线:http: //screencast.com/t/xlwoG9by
Hab*_*bib 10
您的参数顺序错误,应该是:
db_server, db_Name, db_User, db_Pass
Run Code Online (Sandbox Code Playgroud)
目前它是:
"server = {0}; database = {1}; uid = {2}; pwd = {3}"
db_Server db_User db_Pass db_Name
Run Code Online (Sandbox Code Playgroud)
所以你的陈述应该是:
MySqlConnection myConnection = new MySqlConnection(string.Format(
"server = {0}; database = {1}; uid = {2}; pwd = {3}",
db_Server,db_Name, db_User, db_Pass));
Run Code Online (Sandbox Code Playgroud)
编辑:基于评论和讨论,你得到的错误是你正在尝试所有的课程级别的东西.您应该在方法中包含这些行,并在需要的地方调用该方法.就像是:
class MyClass
{
string db_Server = "10.0.0.0";
string db_User = "myUser";
string db_Pass = "myPassword";
string db_Name = "myDatabase";
public MySqlConnection GetConnection()
{
MySqlConnection myConnection = new MySqlConnection(string.Format(
"server = {0}; database = {1}; uid = {2}; pwd = {3}",
db_Server, db_Name, db_User, db_Pass));
return myConnection;
}
}
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
898 次 |
| 最近记录: |