(java)在文件中写小端

Ton*_*ark 17 java endianness filewriter

我正在尝试编写TIFF IFD,我正在寻找一种简单的方法来执行以下操作(这段代码显然是错误的,但它可以解决我想要的问题):

out.writeChar(12) (bytes 0-1)
out.writeChar(259) (bytes 2-3)
out.writeChar(3) (bytes 4-5)
out.writeInt(1) (bytes 6-9)
out.writeInt(1) (bytes 10-13)
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写道:

0c00 0301 0300 0100 0000 0100 0000

我知道如何让写入方法占用正确的字节数(writeInt,writeChar等),但我不知道如何让它以小端编写.谁知道?

xap*_*p4o 32

也许你应该尝试这样的事情:

ByteBuffer buffer = ByteBuffer.allocate(1000); 
buffer.order(ByteOrder.LITTLE_ENDIAN);         
buffer.putChar((char) 12);                     
buffer.putChar((char) 259);                    
buffer.putChar((char) 3);                      
buffer.putInt(1);                              
buffer.putInt(1);                              
byte[] bytes = buffer.array();     
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ZZ *_*der 8

ByteBuffer显然是更好的选择.你也可以写一些像这样的便利函数,

public static void writeShortLE(DataOutputStream out, short value) {
  out.writeByte(value & 0xFF);
  out.writeByte((value >> 8) & 0xFF);
}

public static void writeIntLE(DataOutputStream out, int value) {
  out.writeByte(value & 0xFF);
  out.writeByte((value >> 8) & 0xFF);
  out.writeByte((value >> 16) & 0xFF);
  out.writeByte((value >> 24) & 0xFF);
}
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Chr*_*uin 7

查看ByteBuffer,特别是' order '方法.对于我们这些需要与任何非Java接口的人来说,ByteBuffer是一种祝福.