WCF:许多方法都有相同的Faultcontract

Question

以每个服务上有10个服务和20个方法的项目为例.

所有服务都从具有安全检查的基本服务继承.每种方法的第一件事就是调用安全检查.如果出现问题,则会引发安全性异常.

问题是:我是否需要在每个方法(OperationContract)上指定FaultContract,还是可以在中央定义中执行一次？

Answer 1

您可以通过创建自定义属性来完成此操作.

实现IContractBehavior并将错误添加到Validate方法的每个操作.

void IContractBehavior.Validate(ContractDescription contractDescription, ServiceEndpoint endpoint)
{
   foreach (OperationDescription od in contractDescription.Operations)
      od.Add(yourFault);
}

这是一个详细说明如何实现这一目标的链接.在实际使用的代码下面:

[AttributeUsage(AttributeTargets.Interface, AllowMultiple = false, Inherited = true)]
public class StandardFaultsAttribute : Attribute, IContractBehavior
{
    // this is a list of our standard fault detail classes.
    static Type[] Faults = new Type[]
    {
        typeof(AuthFailure),
        typeof(UnexpectedException),
        typeof(UserFriendlyError)
    };

    public void AddBindingParameters(ContractDescription contractDescription, ServiceEndpoint endpoint, BindingParameterCollection bindingParameters)
    {
    }

    public void ApplyClientBehavior(ContractDescription contractDescription, ServiceEndpoint endpoint, ClientRuntime clientRuntime)
    {
    }

    public void ApplyDispatchBehavior(ContractDescription contractDescription, ServiceEndpoint endpoint, DispatchRuntime dispatchRuntime)
    {
    }

    public void Validate(ContractDescription contractDescription, ServiceEndpoint endpoint)
    {
        foreach (OperationDescription op in contractDescription.Operations)
        {
            foreach (Type fault in Faults)
            {
                op.Faults.Add(MakeFault(fault));
            }
        }
    }

    private FaultDescription MakeFault(Type detailType)
    {
        string action = detailType.Name;
        DescriptionAttribute description = (DescriptionAttribute)                Attribute.GetCustomAttribute(detailType, typeof(DescriptionAttribute));

        if (description != null)
            action = description.Description;
        FaultDescription fd = new FaultDescription(action);
        fd.DetailType = detailType;
        fd.Name = detailType.Name;
        return fd;
    }
}

Answer 2

不,你需要在每一个方法上做到这一点 - WCF相当挑剔,并且需要明确的设置几乎所有东西(最后这确实是一件好事,我确信).

渣