如何在C#中将鼠标光标位置设置到屏幕上的指定点？

Question

如何在C#中将鼠标光标位置设置到屏幕上的指定点？

我必须hacke主板缓冲区接收鼠标和键盘坐标并按???

是否有另一个做点击或我想象？

Answer 1

以下将设置鼠标位置并执行单击:

public static void ClickSomePoint() {
    // Set the cursor position
    System.Windows.Forms.Cursor.Position = new Point(20, 35);

    DoClickMouse(0x2); // Left mouse button down
    DoClickMouse(0x4); // Left mouse button up
}   

static void DoClickMouse(int mouseButton) {
    var input = new INPUT() {
        dwType = 0, // Mouse input
        mi = new MOUSEINPUT() { dwFlags = mouseButton }
    };

    if (SendInput(1, input, Marshal.SizeOf(input)) == 0) { 
        throw new Exception();
    }
}
[StructLayout(LayoutKind.Sequential)]
struct MOUSEINPUT {
    int dx;
    int dy;
    int mouseData;
    public int dwFlags;
    int time;
    IntPtr dwExtraInfo;
}   
struct INPUT {
    public uint dwType;
    public MOUSEINPUT mi;
}   
[DllImport("user32.dll", SetLastError=true)]
static extern uint SendInput(uint cInputs, INPUT input, int size);

请记住,这对用户来说可能非常烦人.

:)

如果要单击表单上的按钮,可以使用该'PerformClick()'方法.

Answer 2

在 Windows 10 中获取和设置鼠标位置：

在 c# .NET Framework 4.0 中使用 Cursor.Position 属性要简单得多

https://learn.microsoft.com/en-us/dotnet/api/system.windows.forms.cursor.position?view=netcore-3.1

    public static void ClickSomePoint()
    {

        // get mouse position
        System.Drawing.Point screenPos = System.Windows.Forms.Cursor.Position;

        // create X,Y point (0,0) explicitly with System.Drawing 
        System.Drawing.Point leftTop = new System.Drawing.Point(0,0);

        // set mouse position
        Cursor.Position = leftTop; 
        Console.WriteLine(screenPos);
    }