我有这样的A类和B类:
class A
{
public:
A(){}
};
class B : public A
{
public:
B() : A()
{
value = 10;
}
int Value()
{
return value;
}
protected:
int value;
}:
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我有这个代码:
int main()
{
A* a = new B();
// how can I access to Value() ? I would like to make that :
int val = a->Value();
// must i cast a to B ? how ?
}
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谢谢你的帮助.
使Value()成为A中的纯虚函数(也添加虚拟析构函数):
class A
{
public:
A(){}
virtual ~A(){}
virtual int Value() = 0;
};
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