用于捕获进程ID的Shell脚本,如果存在则将其终止

Question

我尝试了这个代码,但它无法正常工作

#!/bin/sh

#Find the Process ID for syncapp running instance

PID=`ps -ef | grep syncapp 'awk {print $2}'`

if [[ -z "$PID" ]] then
Kill -9 PID
fi

它在awk附近显示错误.

请给我任何建议.

Answer 1

实际上,最简单的方法是传递如下所示的kill参数:

ps -ef | grep your_process_name | grep -v grep | awk '{print $2}' | xargs kill

希望能帮助到你.

Answer 2

这对我有好处.

PID=`ps -eaf | grep syncapp | grep -v grep | awk '{print $2}'`
if [[ "" !=  "$PID" ]]; then
  echo "killing $PID"
  kill -9 $PID
fi

Answer 3

我用这个命令pkill:

NAME
       pgrep, pkill - look up or signal processes based on name and 
       other attributes

SYNOPSIS
       pgrep [options] pattern
       pkill [options] pattern

DESCRIPTION
       pgrep looks through the currently running processes and lists 
       the process IDs which match the selection criteria to stdout.
       All the criteria have to match.  For example,

              $ pgrep -u root sshd

       will only list the processes called sshd AND owned by root.
       On the other hand,

              $ pgrep -u root,daemon

       will list the processes owned by root OR daemon.

       pkill will send the specified signal (by default SIGTERM) 
       to each process instead of listing them on stdout.

如果您的代码通过解释器(java,python,...)运行,那么进程的名称就是解释器的名称.您需要使用参数--full.这与命令名称和参数匹配.

Answer 4

你可能想写

`ps -ef | grep syncapp | awk '{print $2}'`

但我会赞同@PaulR 的回答——这killall -9 syncapp是一个更好的选择。