使用jquery获取json对象中的元素数

mjs*_*sey 5 jquery json

可能重复:
在jquery中查找数组的长度(大小)

我有一个从php文件返回的json对象,如下所示: -

{"food":[
    {
        "name"       :"Belgian Waffles",
        "price"      :"$5.95",
        "description":"two of our famous Belgian Waffles with plenty of real maple syrup",
        "calories"   :"650"
    },
    {
        "name"       :"Strawberry Belgian Waffles",
        "price"      :"$7.95",
        "description":"light Belgian waffles covered with strawberries and whipped cream",
        "calories"   :"900"
    },
    {
        "name"       :"Berry-Berry Belgian Waffles",
        "price"      :"$8.95",
        "description":"light Belgian waffles covered with an assortment of fresh berries and whipped cream",
        "calories"   :"900"
    }
]}
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这基本上是从物体中返回三个食物元素.如果json数据是动态的并且使用jquery不知道,如何计算返回的元素总数?

nnn*_*nnn 16

假设您已经解析了JSON(或者jQuery已经为您完成了它,如果您使用它的Ajax函数将会这样做)并且您将结果对象放在变量中,只需执行以下操作:

var data = /* your parsed JSON here */
var numberOfElements = data.food.length;
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(注意:没有JSON对象这样的东西:在解析JSON之前它是一个字符串;在你解析它之后它就是一个对象.)

编辑:在评论,你说你不会知道属性被称为food-如果你知道会有一个确切属性和属性将是一个数组,你可以这样做:

var data = /* your object */
var propName;
var numberOfElements;
for (propName in data);
numberOfElements = propName ? data[propName].length : 0;
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如果您知道将只有一个属性,那么您的要求太模糊:如果可能有多个属性,您想要检查其长度?


ahr*_*ren 6

var json = '{"food":[{"name":"Belgian Waffles","price":"$5.95","description":"two of our famous Belgian Waffles with plenty of real maple syrup","calories":"650"},{"name":"Strawberry Belgian Waffles","price":"$7.95","description":"light Belgian waffles covered with strawberries and whipped cream","calories":"900"},{"name":"Berry-Berry Belgian Waffles","price":"$8.95","description":"light Belgian waffles covered with an assortment of fresh berries and whipped cream","calories":"900"}]}';

var obj = JSON.parse(json);

alert(obj.food.length);?
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演示:http://jsfiddle.net/XhG6L/

请注意,IE8及以下版本没有JSON的原生支持,但有一个polyfill可用.

另外,作为另一个注释,jQuery没有在这里做工作 - 这只是普通的旧javascript.

  • 我建议你重新检查一下这个结构.更加一致的按键将使事情变得更加轻松.也许像{categoryName:"food",items:[{name:'',},...]} (2认同)