notepad ++ regex - 删除括号和单独的值

Question

我有清单:

(1, 'Apple', '["5","8"]'),
...
(22, 'Mango', '["5","8"]'),
(23, 'Orange', '["5","8"]'),
(24, 'Banana', '["2","0"]'),
(25, 'Milk', '["2","0"]'),
...
(749, 'Bread', '["2","10"]'),

我想在括号中分隔这样的值

(1, 'Apple', '5', '8'),
...
(22, 'Mango', '5', '8'),
(23, 'Orange', '5', '8'),
(24, 'Banana', '2', '0'),
(25, 'Milk', '2', "0'),
...
(749, 'Bread', '2','10'),

使用Notepad ++"替换为"功能.我也对其他解决方案持开放态度.

谢谢

Answer 1

正则表达式替换所有实例:

'\["(.*?)","(.*?)"\]'

附:

'\1','\2'