广播接收者内部活动

Question

大家好我如何在一个活动中实现一个广播接收器,该活动接收来自服务的意图以及一些int和string类型的参数？

更新:

我在活动下有这个:

 private BroadcastReceiver ReceivefrmSERVICE = new BroadcastReceiver(){

    @Override
    public void onReceive(Context context, Intent intent) {

        Toast.makeText(context, "IN DA BroadCASTER",
                Toast.LENGTH_LONG).show();

    }

   };

我在服务中的一个函数下有这个函数,当选中一个选中的按钮时,它会调用来自另一个活动的事件:

 public void switchSpeaker(int hr, int min){

       Toast.makeText(Server.this, hr +" , " +min, Toast.LENGTH_LONG).show();

       Intent intent = new Intent(this, andRHOME.class);
       //intent.putExtra("sendMessage","1");
        startActivity(intent);
        /*PendingIntent pi = PendingIntent.getService(Server.this, 0, myIntent, 0);
        AlarmManager almmgr = (AlarmManager) getSystemService(ALARM_SERVICE);
        Calendar cldr = Calendar.getInstance();
        int min1 = cldr.get(Calendar.MINUTE);
        cldr.setTimeInMillis(System.currentTimeMillis());
        cldr.add(Calendar.SECOND, 30);
        almmgr.set(AlarmManager.RTC_WAKEUP, cldr.getTimeInMillis(), pi);*/
    }

但它的崩溃？,该怎么办？

Answer 1

BroadcastReceiver receiver = new BroadcastReceiver() {
    @Override
    public void onReceive(Context context, Intent intent) {         
       // DO YOUR STUFF
    }
}

IntentFilter filter = new IntentFilter();

在onResume :(所以你只在前台收到)

filter.addAction(/* the action you want to receive */);
registerReceiver(receiver, filter);

in onPause :( try catch是修复取消注册中的错误,以防它被调用两次)

try {
    unregisterReceiver(receiver);
} catch (IllegalArgumentException e) {
    if (e.getMessage().contains("Receiver not registered")) {
        // Ignore this exception. This is exactly what is desired
        Log.w(TAG,"Tried to unregister the reciver when it's not registered");
    } else {
        // unexpected, re-throw
        throw e;
    }
}