将字节字符串拆分为行

Question

如何将字节字符串拆分为行列表？

在python 2我有:

rest = "some\nlines"
for line in rest.split("\n"):
    print line

上面的代码是为了简洁起见而简化的,但现在经过一些正则表达式处理后,我有一个字节数组rest,我需要迭代这些行.

Answer 1

没有理由转换为字符串.只需给出split字节参数.用字符串拆分字符串,用字节表示字节.

Python 3.2.3 (default, Oct 19 2012, 19:53:57) 
[GCC 4.7.2] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> a = b'asdf\nasdf'
>>> a.split(b'\n')
[b'asdf', b'asdf']

Answer 2

将字节解码为unicode(str),然后使用str.split:

Python 3.2.3 (default, Oct 19 2012, 19:53:16) 
[GCC 4.7.2] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> a = b'asdf\nasdf'
>>> a.split('\n')
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: Type str doesn't support the buffer API
>>> a = a.decode()
>>> a.split('\n')
['asdf', 'asdf']
>>> 

你也可以拆分b'\n',但我想你必须使用字符串而不是字节.因此str,请尽快转换所有输入数据,并仅在代码中使用unicode,并在需要时尽可能将其转换为字节.

Answer 3

试试这个.. .

rest = b"some\nlines"
rest=rest.decode("utf-8")

那么你可以做到rest.split("\n")