use*_*652 3 java servlets nullpointerexception
我正在使用servlet作为重定向页面的控制器.所以,我有以下链接:
<li><a href="actionController?key=contact">Contact</a></li>
<li><a href="actionController?key=support">Request support</a></li>
我希望在我的控制器中接收此参数,并从页面Contact.jsp的页面重定向请求,例如.
因此,我认为这将是:
    contact = request.getParameter("contact");
    support = request.getParameter("support");
    if (contact.equals("contato"))
    {
        RequestDispatcher view = request.getRequestDispatcher("/WEB-INF/center/Contact.jsp");
        view.forward(request, response);        
    }
    else if (support.equals("support"))
    {
        RequestDispatcher view = request.getRequestDispatcher("/WEB-INF/center/Support.jsp");
        view.forward(request, response);
    }
但是,不起作用,是用java.lang.NullPointerException.
谢谢
您的servlet代码似乎与您的HTML片段不匹配.我想你需要写:
    String key = request.getParameter("key");
    if (key != null && key.equals("contact"))
    {
        RequestDispatcher view = request.getRequestDispatcher("/WEB-INF/center/Contact.jsp");
        view.forward(request, response);        
    }
    else if (key != null && key.equals("support"))
    {
        RequestDispatcher view = request.getRequestDispatcher("/WEB-INF/center/Support.jsp");
        view.forward(request, response);
    }