symfony2表单带有参数的querybuilder

Mit*_*oof 23 forms builder query-builder symfony

我想将我的实体放在查询生成器的函数中:

->add( 'weeks', 'entity', array(
    'class' => 'MV\CaravanBundle\Entity\CaravanRow',
    'property' => 'line',
    'query_builder' => function(EntityRepository $er ) use ( $caravan ) {
        return $er->createQueryBuilder('w')
                  ->orderBy('w.dateFrom', 'ASC')
                  ->where('w.caravan = ?', $caravan )
                  ->andWhere('w.visible = 1')
                  ->andWhere('w.booked = 0');
}
Run Code Online (Sandbox Code Playgroud)

但得到消息:

在此上下文中不允许表达"实体\名称"类型

那么提供querybuilder信息的(最佳)方法是什么呢?

Squ*_*zic 39

您应该单独设置参数,如下所示:

->add( 'weeks', 'entity', array(
    'class' => 'MV\CaravanBundle\Entity\CaravanRow',
    'property' => 'line',
    'query_builder' => function(EntityRepository $er ) use ( $caravan ) {
        return $er->createQueryBuilder('w')
                  ->orderBy('w.dateFrom', 'ASC')
                  ->where('w.caravan = ?1')
                  ->andWhere('w.visible = 1')
                  ->andWhere('w.booked = 0')
                  ->setParameter(1, $caravan);
}
Run Code Online (Sandbox Code Playgroud)

您可以使用整数或字符串,但每种语法略有不同.查看文档


Sam*_*Sam 15

我最近遇到了几乎相同的问题.唯一的区别是'query_builder'选项必须在'setDefaultOptions'中设置.基本上,表单是这样创建的:

$builder->add('field', 'query_type', array('id' => 1));
Run Code Online (Sandbox Code Playgroud)

'query_type'类如下所示:

class QueryType extends AbstractType
{
     public function setDefaultOptions(OptionsResolverInterface $options)
     {
              $resolver->setRequired(array('id'));

              $resolver->setNormalizers(array(
                  'query_builder' => function (Options $options, $configs) {
                          return function (EntityRepository $er) use ( $options ) {
                              return $er->getSomething( $options['id'] );

                       };
                  },
              ));
     }
}
Run Code Online (Sandbox Code Playgroud)

我使用setNormalizers函数来访问我的$ options数组,从那里我可以用参数调用querybuilder.

希望这对某人有用!