SQL选择值总和相同的ID

But*_*ers 11 sql select group-by sum

嗨伙计这是我的桌子叫"SAM"

ID  |   S_Date   |  S_MK |   TID   |   Value   |
===============================================
1   | 2012-12-11 |   1   |   112   |   23      |
2   | 2012-12-11 |   2   |   112   |   3       |
3   | 2012-12-11 |   1   |   113   |   22      |
4   | 2012-12-11 |   3   |   114   |   2       |
Run Code Online (Sandbox Code Playgroud)

这应该是我的预期结果:具有相同T_ID的列"值"的总和:

S_Date     | TID   | sum(Value)|
===============================
2012-12-11 | 112   |   26      |
2012-12-11 | 113   |   22      |
2012-12-11 | 114   |   2       |
Run Code Online (Sandbox Code Playgroud)

jue*_*n d 15

select S_Date, TID, sum(Value)
from SAM
group by S_Date, TID
Run Code Online (Sandbox Code Playgroud)