JTable上的JPopupMenu - >获取创建菜单的单元格

Question

我有一种情况,我在右键单击JTable时创建了一个弹出菜单.创建弹出菜单的标准方法:

aJTable.setComponentPopupMenu(rightClickMenu);

之后在注册的操作中,我无法找到右键单击哪个单元格以显示该弹出菜单.

rightClickMenuItem.addActionListener(new AbstractAction() {
    @Override
    public void actionPerformed(ActionEvent e) {
        // Work out what cell was right clicked to generate the menu
    }

});

关于你如何做到这一点的任何想法？

Answer 1

令人惊讶的事实是:安装了componentPopupMenu后,mouseListener永远不会看到作为popupTrigger的mouseEvent(原因是显示componentPopup由BasicLookAndFeel安装的AWTEventListener全局处理,并且该侦听器使用该事件).

看到该触发器的mousePosition的唯一地方是getPopupLocation(MouseEvent),因此获取它的唯一可靠方法(用于执行依赖于位置的配置/操作)是@Mad的建议,即重写该方法并将值存储在某处以后用.

下面的代码段使用clientProperty作为存储位置:

final JTable table = new JTable(new AncientSwingTeam()) {

    @Override
    public Point getPopupLocation(MouseEvent event) {
        setPopupTriggerLocation(event);
        return super.getPopupLocation(event);
    }

    protected void setPopupTriggerLocation(MouseEvent event) {
        putClientProperty("popupTriggerLocation", 
                event != null ? event.getPoint() : null);
    }
};
JPopupMenu popup = new JPopupMenu();
Action action = new AbstractAction("show trigger location") {

    @Override
    public void actionPerformed(ActionEvent e) {
        JPopupMenu parent = (JPopupMenu) SwingUtilities.getAncestorOfClass(
                JPopupMenu.class, (Component) e.getSource());
        JTable invoker = (JTable) parent.getInvoker();
        Point p = (Point) invoker.getClientProperty("popupTriggerLocation");
        String output = p != null ? "row/col: " 
             + invoker.rowAtPoint(p) + "/" + invoker.columnAtPoint(p) : null; 
        System.out.println(output);
    }
};
popup.add(action);
popup.add("dummy2");
table.setComponentPopupMenu(popup);