AWK命令将更新纪元时间更改为在同一行上列出纪元

Question

所以现在我有:

echo -n "Enter Path (or File if in directory) to Convert: " ; read FILE ; cat $FILE | awk '{print strftime("%c",$1)} {print}'

输入要转换的文件或路径时,将打印以下内容:

Tue 04 Dec 2012 09:48:43 PM PST
1354686523
Wed 05 Dec 2012 09:47:38 PM PST
1354772858
Thu 06 Dec 2012 09:47:39 PM PST
1354859259
Fri 07 Dec 2012 09:46:08 PM PST
1354945568

以上仅是一个示例日期.这是完美的,但我怎么能让它在同一条线上？所以它在文件中显示每个日期,如下所示:

Tue 04 Dec 2012 09:48:43 PM PST  --  1354686523
Wed 05 Dec 2012 09:47:38 PM PST  --  1354772858
Thu 06 Dec 2012 09:47:39 PM PST  --  1354859259
Fri 07 Dec 2012 09:46:08 PM PST  --  1354945568

非常感谢!!

Answer 1

你可以尝试:

awk '{ printf "%s -- %s\n", strftime("%c",$1), $0 }' file