使用ASP.NET Web API将HTTP POST转换为多对多关系

Question

我是ASP.net的新手(以及一般的编程),我在构建Web API时遇到了麻烦.更具体地说,我需要在这两方面提供帮助:

1. 如何配置我DOCcontroller发布新文档(DOC表).
2. 如何制作实际的ajax帖子 - 我在传递EXT_GUID参数时遇到问题.当我试图发布时,我得到一个错误."无法将多个参数(doc和parentOwner)绑定到请求的内容."

基本上这是一个简单的文档管理系统.我希望通过让用户从外部数据库(EXT_GUID字段)提供GUID作为过滤器/参数来获取/发布文档(DOC).每个文档可以有多个EXT_GUID,每个EXT_GUID可以有多个文档(DOC).您可以假设我们在http帖子之前填充了EXT_GUID字段.

这是DOCcontroller代码

//POST api/DOC
public HttpResponseMessage PostDOC(DOC doc, List<string> parentOwners)
{
    if (ModelState.IsValid)
    {            
        var parents = db.BIMs.Where(bx => parentOwners.Contains(bx.EXT_GUID));

        foreach (var p in parents)
        doc.Owners.Add(p);

        db.DOCs.Add(doc);
        db.SaveChanges();

        HttpResponseMessage response = Request.CreateResponse(HttpStatusCode.Created, doc);
        response.Headers.Location = new Uri(Url.Link("DefaultApi", new { id = doc.Id }));
        return response;
    }
    else
    {
        return Request.CreateResponse(HttpStatusCode.BadRequest);
    }
}

这是我的模型设置 - EntityFramework codefirst东西

public class EXT
{
    public int Id { get; set; }
    public string EXT_GUID { get; set; }
    public int ProjectID { get; set; }
    public virtual ICollection<DOC> DOCs { get; set; }
}

public class DOC
{
    public int Id { get; set; }
    public int ProjectID { get; set; }
    public string Subject { get; set; }
    public string Link { get; set; }
    public virtual ICollection<EXT> EXTs { get; set; }
}

这是更多存储模型......

public StoreDBContext() : base("name=StoreDBContext")
{
}
public DbSet<EXT> EXTs { get; set; }
public DbSet<DOC> DOCs { get; set; }
protected override void OnModelCreating(DbModelBuilder modelBuilder)
{
    //Set FLUENT API config for many to many here
    modelBuilder.Entity<EXT>()
    .HasMany(a => a.DOCs)
    .WithMany()
    .Map(x =>
    {
        x.MapLeftKey("EXT_Id");
        x.MapRightKey("DOC_Id");
        x.ToTable("EXTsDOCs");
    });
}

AJAX代码

function AddDOC() {
    var parentOwner = "{\"" + $('#txtaddEXT').val() + "\"}";
    jQuery.support.cors = true;
    var DOC = {
        ProjectId: ProjectID,
        Subject: $('#txtaddDOCSubject').val(),
        Link: $('#txtaddDOCLink').val(),
            parentOwner: parentOwner
    };

    $.ajax({
        url: "http://localhost:54171/api/DOC/",
        type: 'POST',
        data: JSON.stringify(DOC),
        contentType: "application/json;charset=utf-8",
        success: function (data) {
            WriteResponse(data);
        },
        error: function (x, y, z) {
            alert(x + '\n' + y + '\n' + z);
        }
    });
}

Answer 1

您从客户端收到的内容和您将在数据库中保存的内容是两件不同的事情。您的 doc 对象没问题：

var DOC = {
    ProjectId: ProjectID,
    Subject: $('#txtaddDOCSubject').val(),
    Link: $('#txtaddDOCLink').val(),
    parentOwner: parentOwner
};

现在您需要更改服务器逻辑。制作一个这样的模型：

public class DocReceivedModel 
{
    public int ProjectID { get; set; }
    public string Subject { get; set; }
    public string Link { get; set; }
    public List<string> parentOwner { get; set; }
}

那么你的 PostDOC 方法将是：

            public HttpResponseMessage PostDOC(DocReceivedModel docReceived)
            {
                if (ModelState.IsValid)
                {
                    Doc newDoc = new Doc();
                    newDoc.ProjectID = docReceived.ProjectID
                    newDoc.Subject = docReceived.Subject
                    newDoc.Link = docReceived.Link

                    var parents = db.BIMs.Where(bx => docReceived.parentOwners.Contains(bx.EXT_GUID));
                    foreach (var p in parents)
                        newDoc.Owners.Add(p);
                            // I not see in your model Owners, maybe this is EXTs but I suppose you catch the idea

                    db.DOCs.Add(newDoc);
                    db.SaveChanges();

                    HttpResponseMessage response = Request.CreateResponse(HttpStatusCode.Created, newDoc);
                    response.Headers.Location = new Uri(Url.Link("DefaultApi", new {id = newDoc.Id}));
                    return response;
                }
                else
                {
                    return Request.CreateResponse(HttpStatusCode.BadRequest);
                }
            }