C ++ 11如何代理仅具有名称和父类的类函数?

myW*_*SON 4 c++ boost boost-mpl boost-preprocessor c++11

我想知道是否有可能使用boost :: mpl / preprocessor或某些noce C ++ 11功能从类类型和函数名称创建函数代理。

说我们有:

  inline void set_email(const ::std::string& value);
  inline void set_email(const char* value);
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内部类电子邮件。我们知道有set_email函数,我们想用API创建一个prox类,例如

PROXY(Email, set_email, MyEmail)

Email * email = new Email();
MyEmail * myEmail = new MyEmail(email);
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并且有能力调用任何set_email重载。是否有可能以及如何创建这样的类来代理任何数量的不知道那里类型(仅名称)的重载函数?

Dra*_*rax 5

这个怎么样:

proxy_macro.hpp

#include <type_traits>
#include <utility>

#define PROXY(proxified, member_function, proxy_name)                                                                           \
  class proxy_name                                                                                                              \
  {                                                                                                                             \
  private:                                                                                                                      \
    proxified & ref_;                                                                                                           \
                                                                                                                                \
  public:                                                                                                                       \
    proxy_name(proxified &ref)                                                                                                  \
      : ref_(ref)                                                                                                               \
      {                                                                                                                         \
      }                                                                                                                         \
                                                                                                                                \
    /* general version */                                                                                                       \
    template<typename ... Args>                                                                                                 \
    auto member_function(Args&& ... args)                                                                                       \
    -> typename std::enable_if<!std::is_void<decltype(ref_.member_function(std::forward<Args>(args)...))>::value,               \
                               decltype(ref_.member_function(std::forward<Args>(args)...))>::type                               \
      {                                                                                                                         \
        return (ref_.member_function(std::forward<Args>(args)...));                                                             \
      }                                                                                                                         \
                                                                                                                                \
    /* void return type version */                                                                                              \
    template<typename ... Args>                                                                                                 \
    auto member_function(Args&& ... args)                                                                                       \
    -> typename std::enable_if<std::is_void<decltype(ref_.member_function(std::forward<Args>(args)...))>::value,                \
                               void>::type                                                                                      \
      {                                                                                                                         \
        ref_.member_function(std::forward<Args>(args)...);                                                                      \
      }                                                                                                                         \
                                                                                                                                \
  };
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这对我来说可以编译并正常工作g++ 4.7

#include "proxy_macro.hpp"

#include <iostream>
#include <string>

class   Email
{
public:  
  void set_email(const ::std::string& value)
  {
    std::cout << value << std::endl;
  }

  void set_email(const char* value)
  {
    std::cout << value << std::endl;
  }

  int   set_email()
  {
    return (42);
  }

};

PROXY(Email, set_email, MyEmail)

int main(void)
{
  Email   mail;
  MyEmail my_mail(mail);

  std::string str = "test string";
  const char * ptr = "test char pointer";

  my_mail.set_email(str);
  my_mail.set_email(ptr);

  std::cout << "test return: " << my_mail.set_email() << std::endl;

  return (0);
}
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编辑(感谢评论,版本较小)

proxy_macro.hpp

#include <type_traits>
#include <utility>

#define PROXY(proxified, member_function, proxy_name)                \
  class proxy_name                                                   \
  {                                                                  \
  private:                                                           \
    proxified & ref_;                                                \
                                                                     \
  public:                                                            \
    proxy_name(proxified &ref)                                       \
      : ref_(ref)                                                    \
      {                                                              \
      }                                                              \
                                                                     \
    template<typename ... Args>                                      \
    auto member_function(Args&& ... args)                            \
    -> decltype(ref_.member_function(std::forward<Args>(args)...))   \
      {                                                              \
        return (ref_.member_function(std::forward<Args>(args)...));  \
      }                                                              \
  };
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  • 从`void`函数返回`void`是合法的,因此我认为不需要特殊情况。`void foo(){}; void bar(){return foo(); }`是有效的(您编写的那种代码完全受支持)。 (2认同)