如何将锚标记扩展到列表项的底部？我知道我可以将锚点放在列表项标签上,但是这违反了XHTML 1.0严格的合规性,所以我不能这样做.
<html>
<head>
<style>
#listWrapper { text-align:center;}
#list { margin-left: 0px auto; margin-right: 0px auto; width: 100%; min-height: 100%; height:100%; margin-bottom: 10px; margin-top: 0px;}
#list ul { padding: 5px 10px 10px 10px; margin: 0; min-height: 100%;}
#list li { clear:both; font-weight:bolder; height:auto; border-bottom: 1px solid Silver; border-left: 1px solid Silver; font-size:x-small; border-right: 1px solid Silver; list-style-type: none;}
#list a:hover { background-color: red;}
#list a { display:block; cursor:pointer; text-decoration: none; text-align:left; vertical-align:top; }
#list h3 { background-color:Silver; vertical-align:top; font-size:larger; }
#list img { height:auto; margin: 8px; float:left; vertical-align:top; border:solid 1px Silver;}
</style>
</head>
<body>
<div id="listWrapper">
<div id="list">
<ul>
<li>
<h3>title</h3>
<a href="#">
<img src="/images/x.jpg" alt="" />
Lorem ipsun........
</a>
<div style="clear:both;" />
</li>
<li>
<h3>title</h3>
<a href="#">
<img src="/images/x.jpg" alt="" />
Lorem ipsun........
</a>
<div style="clear:both;" />
</li>
</ul>
</div>
</div>
</body>
</html>
sim*_*831 52
你的答案组合修复了它.多谢....
#list ul { display: block; }
#list li { display: block;}
#list a { display:block; height:100%; }
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